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Processing file inclusion directives using mutual recursion



Planned maintenance scheduled April 23, 2019 at 00:00UTC (8:00pm US/Eastern)
Announcing the arrival of Valued Associate #679: Cesar Manara
Unicorn Meta Zoo #1: Why another podcast?Parse emails and create HTML markup from attachmentsPython code to write simple VPK archive filesReusable, generic save methodMod maker (creates XML files to be used as mods)Finding all non-empty directories and their files on an SFTP server with ParamikoGroup duplicate files (part 3)Console application to search for files that contain a match for a regexParsing million words of list in python regular expression is slowIdentify Duplicate FilesC Recursive Opendir Wrapper to Sort Directories First (ascending/descending)



.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








1












$begingroup$


I am preprocessing a set of files where one file is included in another file with an include tag like shown below:



file A



include file B
include file C
contents of file A
include file D
contents of file A


Here I need to replace the include tags with contents of each of the respective files, just like what a compiler does. I have two functions for that:



def parseContent(self, rdbFilePath, content):
finalContent = self.removeComments(content)
includeFileSearch = re.compile(r'(?P<tag>(s)*include+(s*)"(s*)(?P<file>[a-zA-Z0-9._/]*)")')
for includes in includeFileSearch.finditer(finalContent):
finalContent = re.sub(includes.group('tag'),self.parseIncludes(rdbFilePath, includes.group('file')), finalContent)
return finalContent

def parseIncludes(self, rdbFilePath, file):
path = rdbFilePath + "/" + file
f = open(path)
pathDir = os.path.dirname(path)
includedFileContent = self.parseContent(pathDir, f.read())
return includedFileContent


As you can see, functions parseContent and parseIncludes call each other recursively to replace all the include tags in every file. The logic works fine. But it takes a bit long time to execute. Is there any better way to do the same with lesser execution time?










share|improve this question









New contributor




Hari Krishnan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$











  • $begingroup$
    Are you parsing XML with regex? You need to read this
    $endgroup$
    – AJNeufeld
    7 mins ago

















1












$begingroup$


I am preprocessing a set of files where one file is included in another file with an include tag like shown below:



file A



include file B
include file C
contents of file A
include file D
contents of file A


Here I need to replace the include tags with contents of each of the respective files, just like what a compiler does. I have two functions for that:



def parseContent(self, rdbFilePath, content):
finalContent = self.removeComments(content)
includeFileSearch = re.compile(r'(?P<tag>(s)*include+(s*)"(s*)(?P<file>[a-zA-Z0-9._/]*)")')
for includes in includeFileSearch.finditer(finalContent):
finalContent = re.sub(includes.group('tag'),self.parseIncludes(rdbFilePath, includes.group('file')), finalContent)
return finalContent

def parseIncludes(self, rdbFilePath, file):
path = rdbFilePath + "/" + file
f = open(path)
pathDir = os.path.dirname(path)
includedFileContent = self.parseContent(pathDir, f.read())
return includedFileContent


As you can see, functions parseContent and parseIncludes call each other recursively to replace all the include tags in every file. The logic works fine. But it takes a bit long time to execute. Is there any better way to do the same with lesser execution time?










share|improve this question









New contributor




Hari Krishnan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$











  • $begingroup$
    Are you parsing XML with regex? You need to read this
    $endgroup$
    – AJNeufeld
    7 mins ago













1












1








1





$begingroup$


I am preprocessing a set of files where one file is included in another file with an include tag like shown below:



file A



include file B
include file C
contents of file A
include file D
contents of file A


Here I need to replace the include tags with contents of each of the respective files, just like what a compiler does. I have two functions for that:



def parseContent(self, rdbFilePath, content):
finalContent = self.removeComments(content)
includeFileSearch = re.compile(r'(?P<tag>(s)*include+(s*)"(s*)(?P<file>[a-zA-Z0-9._/]*)")')
for includes in includeFileSearch.finditer(finalContent):
finalContent = re.sub(includes.group('tag'),self.parseIncludes(rdbFilePath, includes.group('file')), finalContent)
return finalContent

def parseIncludes(self, rdbFilePath, file):
path = rdbFilePath + "/" + file
f = open(path)
pathDir = os.path.dirname(path)
includedFileContent = self.parseContent(pathDir, f.read())
return includedFileContent


As you can see, functions parseContent and parseIncludes call each other recursively to replace all the include tags in every file. The logic works fine. But it takes a bit long time to execute. Is there any better way to do the same with lesser execution time?










share|improve this question









New contributor




Hari Krishnan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




I am preprocessing a set of files where one file is included in another file with an include tag like shown below:



file A



include file B
include file C
contents of file A
include file D
contents of file A


Here I need to replace the include tags with contents of each of the respective files, just like what a compiler does. I have two functions for that:



def parseContent(self, rdbFilePath, content):
finalContent = self.removeComments(content)
includeFileSearch = re.compile(r'(?P<tag>(s)*include+(s*)"(s*)(?P<file>[a-zA-Z0-9._/]*)")')
for includes in includeFileSearch.finditer(finalContent):
finalContent = re.sub(includes.group('tag'),self.parseIncludes(rdbFilePath, includes.group('file')), finalContent)
return finalContent

def parseIncludes(self, rdbFilePath, file):
path = rdbFilePath + "/" + file
f = open(path)
pathDir = os.path.dirname(path)
includedFileContent = self.parseContent(pathDir, f.read())
return includedFileContent


As you can see, functions parseContent and parseIncludes call each other recursively to replace all the include tags in every file. The logic works fine. But it takes a bit long time to execute. Is there any better way to do the same with lesser execution time?







python performance recursion regex file






share|improve this question









New contributor




Hari Krishnan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




Hari Krishnan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited 7 mins ago









200_success

131k17157422




131k17157422






New contributor




Hari Krishnan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 16 mins ago









Hari KrishnanHari Krishnan

1062




1062




New contributor




Hari Krishnan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Hari Krishnan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Hari Krishnan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











  • $begingroup$
    Are you parsing XML with regex? You need to read this
    $endgroup$
    – AJNeufeld
    7 mins ago
















  • $begingroup$
    Are you parsing XML with regex? You need to read this
    $endgroup$
    – AJNeufeld
    7 mins ago















$begingroup$
Are you parsing XML with regex? You need to read this
$endgroup$
– AJNeufeld
7 mins ago




$begingroup$
Are you parsing XML with regex? You need to read this
$endgroup$
– AJNeufeld
7 mins ago










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