Transforming an array: take the square root of each perfect square, else square the number Planned maintenance scheduled April 23, 2019 at 23:30UTC (7:30pm US/Eastern) Announcing the arrival of Valued Associate #679: Cesar Manara Unicorn Meta Zoo #1: Why another podcast?
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Transforming an array: take the square root of each perfect square, else square the number
Planned maintenance scheduled April 23, 2019 at 23:30UTC (7:30pm US/Eastern)
Announcing the arrival of Valued Associate #679: Cesar Manara
Unicorn Meta Zoo #1: Why another podcast?
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$begingroup$
SquareOrSquareRoot should get an array of integers and return a new array. If the number at index i is a "square" number the returned array at index i should have its square root. If the original number is not a "square" number then the returned array in index i should be the number squared.
Coming from Python (where this could be done in a single line using list comprehension or using map), I find it very odd that this is probably one of the shortest ways to achieve that in Go (please prove me wrong).
package main
import (
"fmt"
"math"
)
func SquareOrSquareRoot(arr []int) []int
arr_to_return := make([]int, len(arr))
for index, value := range arr
val_sqrt := math.Sqrt(float64(value))
if val_sqrt == math.Trunc(val_sqrt)
arr_to_return[index] = int(val_sqrt)
else
arr_to_return[index] = value * value
return arr_to_return
func main()
arr := []int100, 101, 5, 5, 1, 1
fmt.Println(SquareOrSquareRoot(arr))
// [10 10201 25 25 1 1]
go
edited Jul 28 '17 at 4:34
200_success
131k17157422
asked Jul 28 '17 at 1:02
DeepSpaceDeepSpace
31519
$endgroup$
bumped to the homepage by Community♦ 12 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
add a comment |
$begingroup$
SquareOrSquareRoot should get an array of integers and return a new array. If the number at index i is a "square" number the returned array at index i should have its square root. If the original number is not a "square" number then the returned array in index i should be the number squared.
Coming from Python (where this could be done in a single line using list comprehension or using map), I find it very odd that this is probably one of the shortest ways to achieve that in Go (please prove me wrong).
package main
import (
"fmt"
"math"
)
func SquareOrSquareRoot(arr []int) []int
arr_to_return := make([]int, len(arr))
for index, value := range arr
val_sqrt := math.Sqrt(float64(value))
if val_sqrt == math.Trunc(val_sqrt)
arr_to_return[index] = int(val_sqrt)
else
arr_to_return[index] = value * value
return arr_to_return
func main()
arr := []int100, 101, 5, 5, 1, 1
fmt.Println(SquareOrSquareRoot(arr))
// [10 10201 25 25 1 1]
go
edited Jul 28 '17 at 4:34
200_success
131k17157422
asked Jul 28 '17 at 1:02
DeepSpaceDeepSpace
31519
$endgroup$
bumped to the homepage by Community♦ 12 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
$begingroup$
Where you say "array" you mean, and should say, "slice". Arrays and slices are different things in Go, see "The Go Blog - Arrays, slices (and strings): The mechanics of 'append".
$endgroup$
– Dave C
Sep 24 '17 at 16:39
add a comment |
$begingroup$
SquareOrSquareRoot should get an array of integers and return a new array. If the number at index i is a "square" number the returned array at index i should have its square root. If the original number is not a "square" number then the returned array in index i should be the number squared.
Coming from Python (where this could be done in a single line using list comprehension or using map), I find it very odd that this is probably one of the shortest ways to achieve that in Go (please prove me wrong).
package main
import (
"fmt"
"math"
)
func SquareOrSquareRoot(arr []int) []int
arr_to_return := make([]int, len(arr))
for index, value := range arr
val_sqrt := math.Sqrt(float64(value))
if val_sqrt == math.Trunc(val_sqrt)
arr_to_return[index] = int(val_sqrt)
else
arr_to_return[index] = value * value
return arr_to_return
func main()
arr := []int100, 101, 5, 5, 1, 1
fmt.Println(SquareOrSquareRoot(arr))
// [10 10201 25 25 1 1]
go
edited Jul 28 '17 at 4:34
200_success
131k17157422
asked Jul 28 '17 at 1:02
DeepSpaceDeepSpace
31519
$endgroup$
SquareOrSquareRoot should get an array of integers and return a new array. If the number at index i is a "square" number the returned array at index i should have its square root. If the original number is not a "square" number then the returned array in index i should be the number squared.
Coming from Python (where this could be done in a single line using list comprehension or using map), I find it very odd that this is probably one of the shortest ways to achieve that in Go (please prove me wrong).
package main
import (
"fmt"
"math"
)
func SquareOrSquareRoot(arr []int) []int
arr_to_return := make([]int, len(arr))
for index, value := range arr
val_sqrt := math.Sqrt(float64(value))
if val_sqrt == math.Trunc(val_sqrt)
arr_to_return[index] = int(val_sqrt)
else
arr_to_return[index] = value * value
return arr_to_return
func main()
arr := []int100, 101, 5, 5, 1, 1
fmt.Println(SquareOrSquareRoot(arr))
// [10 10201 25 25 1 1]
go
go
edited Jul 28 '17 at 4:34
200_success
131k17157422
asked Jul 28 '17 at 1:02
DeepSpaceDeepSpace
31519
edited Jul 28 '17 at 4:34
200_success
131k17157422
asked Jul 28 '17 at 1:02
DeepSpaceDeepSpace
31519
edited Jul 28 '17 at 4:34
200_success
131k17157422
edited Jul 28 '17 at 4:34
200_success
131k17157422
edited Jul 28 '17 at 4:34
200_success
131k17157422
131k17157422
asked Jul 28 '17 at 1:02
DeepSpaceDeepSpace
31519
asked Jul 28 '17 at 1:02
DeepSpaceDeepSpace
31519
asked Jul 28 '17 at 1:02
DeepSpaceDeepSpace
31519
31519
bumped to the homepage by Community♦ 12 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
bumped to the homepage by Community♦ 12 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
$begingroup$
Where you say "array" you mean, and should say, "slice". Arrays and slices are different things in Go, see "The Go Blog - Arrays, slices (and strings): The mechanics of 'append".
$endgroup$
– Dave C
Sep 24 '17 at 16:39
add a comment |
$begingroup$
Where you say "array" you mean, and should say, "slice". Arrays and slices are different things in Go, see "The Go Blog - Arrays, slices (and strings): The mechanics of 'append".
$endgroup$
– Dave C
Sep 24 '17 at 16:39
$begingroup$
Where you say "array" you mean, and should say, "slice". Arrays and slices are different things in Go, see "The Go Blog - Arrays, slices (and strings): The mechanics of 'append".
$endgroup$
– Dave C
Sep 24 '17 at 16:39
$begingroup$
Where you say "array" you mean, and should say, "slice". Arrays and slices are different things in Go, see "The Go Blog - Arrays, slices (and strings): The mechanics of 'append".
$endgroup$
– Dave C
Sep 24 '17 at 16:39
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Naming conventions aside (short names in camelCase are typically used in Go), this is the right way of doing what you want. The authors of Go have a different view of what is more readable & maintainable than the authors of Python :-)
answered Jul 28 '17 at 13:03
TedTed
635212
$endgroup$
add a comment |
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$begingroup$
Naming conventions aside (short names in camelCase are typically used in Go), this is the right way of doing what you want. The authors of Go have a different view of what is more readable & maintainable than the authors of Python :-)
answered Jul 28 '17 at 13:03
TedTed
635212
$endgroup$
add a comment |
$begingroup$
Naming conventions aside (short names in camelCase are typically used in Go), this is the right way of doing what you want. The authors of Go have a different view of what is more readable & maintainable than the authors of Python :-)
answered Jul 28 '17 at 13:03
TedTed
635212
$endgroup$
add a comment |
$begingroup$
Naming conventions aside (short names in camelCase are typically used in Go), this is the right way of doing what you want. The authors of Go have a different view of what is more readable & maintainable than the authors of Python :-)
answered Jul 28 '17 at 13:03
TedTed
635212
$endgroup$
Naming conventions aside (short names in camelCase are typically used in Go), this is the right way of doing what you want. The authors of Go have a different view of what is more readable & maintainable than the authors of Python :-)
answered Jul 28 '17 at 13:03
TedTed
635212
answered Jul 28 '17 at 13:03
TedTed
635212
answered Jul 28 '17 at 13:03
TedTed
635212
answered Jul 28 '17 at 13:03
TedTed
635212
635212
add a comment |
add a comment |
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$begingroup$
Where you say "array" you mean, and should say, "slice". Arrays and slices are different things in Go, see "The Go Blog - Arrays, slices (and strings): The mechanics of 'append".
$endgroup$
– Dave C
Sep 24 '17 at 16:39