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Direct mapping from a CSV data lake (with headers) to an XML output

.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;

0

$begingroup$

Based on my question from this link (general case for property mappings to a class object), some help with a code review would be greatly appreciated.

Right now, the "general case" - skipping the first column in a data lake, and then iterating over columns 1 to N - is being handled with an iterator. This solution would be done justice if it could be done completely in LINQ, with a single lambda expression.

Here are the code snippets I am hoping to improve:

var yValues = new List<Schema.W[]>();
Schema.W[] y = null;
for (int i = 0; i < headers.Length; i++)
 
 y = data
 .Select((z) => new Schema.W
 
 property_0 = z[0],
 property_1 = decimal.Parse(z[i + 1])
 ).ToArray();
 yValues.Add(y);
 
 }

And then finally:

var finalList = new List<Schema.W>();
Schema.W = null;
for (int i = 0; i < headers.Length; i++)
 
 mapping = new Schema.W
 
 innerNodes = yValues[i]
 ;
 finalList.Add(mapping);
 

Looking forward to contributing as time goes on.

c# linq lambda

share|improve this question

edited 26 secs ago

Sartaj Hundal

asked 12 mins ago

Sartaj HundalSartaj Hundal

1

New contributor

Sartaj Hundal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

add a comment | 

0

$begingroup$

Based on my question from this link (general case for property mappings to a class object), some help with a code review would be greatly appreciated.

Right now, the "general case" - skipping the first column in a data lake, and then iterating over columns 1 to N - is being handled with an iterator. This solution would be done justice if it could be done completely in LINQ, with a single lambda expression.

Here are the code snippets I am hoping to improve:

var yValues = new List<Schema.W[]>();
Schema.W[] y = null;
for (int i = 0; i < headers.Length; i++)
 
 y = data
 .Select((z) => new Schema.W
 
 property_0 = z[0],
 property_1 = decimal.Parse(z[i + 1])
 ).ToArray();
 yValues.Add(y);
 
 }

And then finally:

var finalList = new List<Schema.W>();
Schema.W = null;
for (int i = 0; i < headers.Length; i++)
 
 mapping = new Schema.W
 
 innerNodes = yValues[i]
 ;
 finalList.Add(mapping);
 

Looking forward to contributing as time goes on.

c# linq lambda

share|improve this question

edited 26 secs ago

Sartaj Hundal

asked 12 mins ago

Sartaj HundalSartaj Hundal

1

New contributor

Sartaj Hundal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

add a comment | 

$begingroup$

Based on my question from this link (general case for property mappings to a class object), some help with a code review would be greatly appreciated.

Right now, the "general case" - skipping the first column in a data lake, and then iterating over columns 1 to N - is being handled with an iterator. This solution would be done justice if it could be done completely in LINQ, with a single lambda expression.

Here are the code snippets I am hoping to improve:

var yValues = new List<Schema.W[]>();
Schema.W[] y = null;
for (int i = 0; i < headers.Length; i++)
 
 y = data
 .Select((z) => new Schema.W
 
 property_0 = z[0],
 property_1 = decimal.Parse(z[i + 1])
 ).ToArray();
 yValues.Add(y);
 
 }

And then finally:

var finalList = new List<Schema.W>();
Schema.W = null;
for (int i = 0; i < headers.Length; i++)
 
 mapping = new Schema.W
 
 innerNodes = yValues[i]
 ;
 finalList.Add(mapping);
 

Looking forward to contributing as time goes on.

c# linq lambda

share|improve this question

edited 26 secs ago

Sartaj Hundal

asked 12 mins ago

Sartaj HundalSartaj Hundal

1

New contributor

Sartaj Hundal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

var yValues = new List<Schema.W[]>();
Schema.W[] y = null;
for (int i = 0; i < headers.Length; i++)
 
 y = data
 .Select((z) => new Schema.W
 
 property_0 = z[0],
 property_1 = decimal.Parse(z[i + 1])
 ).ToArray();
 yValues.Add(y);
 
 }

var finalList = new List<Schema.W>();
Schema.W = null;
for (int i = 0; i < headers.Length; i++)
 
 mapping = new Schema.W
 
 innerNodes = yValues[i]
 ;
 finalList.Add(mapping);
 

share|improve this question

edited 26 secs ago

Sartaj Hundal

asked 12 mins ago

Sartaj HundalSartaj Hundal

1

New contributor

Sartaj Hundal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

edited 26 secs ago

Sartaj Hundal

asked 12 mins ago

Sartaj HundalSartaj Hundal

1

New contributor

Sartaj Hundal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 12 mins ago

Sartaj HundalSartaj Hundal

1

New contributor

Sartaj Hundal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 12 mins ago

Sartaj HundalSartaj Hundal

1