Iterative solution to train problem to practice class and object basicsGenerically encapsulating random generators and distributions into a class templateGeneric pixel class to seamlessly alpha-blend and convert between different pixel structure layoutsTracker for object construction, copy, and movement

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Iterative solution to train problem to practice class and object basics


Generically encapsulating random generators and distributions into a class templateGeneric pixel class to seamlessly alpha-blend and convert between different pixel structure layoutsTracker for object construction, copy, and movement













0












$begingroup$


Ive done a little bit of programming in the past, mostly just dabbling.
After a long time of not touching an IDE, I am getting back into it. I just threw this quick project together to make sure I remember how to use classes and objects before I start playing with bigger projects.



I would love a quick critique to make sure there arent any glaring poor practices that could develop into bad habbits in the future.



I know the standard way to solve this problem is just time = distance/(velA+velB), but what would the point of using objects be if i didnt have the objects do something and change their status in someway?



what do you think, looks good?



/*

The goal for this practice program is to solve the common math word problem below using classes and objects.
I feel that using iterations rather than the basic math formula to solve, although clearly less efficient, would be more true to thinking in terms of objects.

Train A, traveling X miles per hour (mph), leaves Westford heading toward Eastford, 260 miles away.
At the same time Train B, traveling Y mph, leaves Eastford heading toward Westford.
When do the two trains meet? How far from each city do they meet?

*/

#include "pch.h"
#include <iostream>
using namespace std;

class Train

public:
Train(int, int);
int getLocation();
void update();
private:
int location, velocity;
;

Train::Train(int loc, int vel) //to initialize the train object and set its location and velocity

location = loc;
velocity = vel;


int Train::getLocation() // returns the location of the train object

return location;


void Train::update() // updates the train object for one iteration

location += velocity;


int main()

int velA, velB, distance; //to take the values from the user input
int time; // to keep track of the number of iterations
// time is declared here so it can be used outside of the for loop


//input
cout << "Enter velocity of the train from Westford:n";
cin >> velA;
cout << "nnEnter velocity of the train from Eastford:n";
cin >> velB;
cout << "nnEnter the distance between Westford and Eastford:n";
cin >> distance;

//initialize each train
Train trainA(0, velA);
Train trainB(distance, 0 - velB); //location of trainB is distance because the distance between an x coordinate at 0 and another x coordinate is equal to the second x coordinate
//the velocity of trainB is the negative of velB because it is traveling in the opposite direction of trainA

//run the sim
for (time = 0; trainA.getLocation() < trainB.getLocation(); time++)

trainA.update();
trainB.update();


//output
cout << "nnThe Trains pass eachother after " << time << " hours."
<< "nAt that time, the Westford train is " << trainA.getLocation() << " miles from Westfordn"
<< "and the Eastford train is " << distance - trainB.getLocation() << " miles from Eastford.nn";

return 0;









share







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Mickey Brenneman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$
















    0












    $begingroup$


    Ive done a little bit of programming in the past, mostly just dabbling.
    After a long time of not touching an IDE, I am getting back into it. I just threw this quick project together to make sure I remember how to use classes and objects before I start playing with bigger projects.



    I would love a quick critique to make sure there arent any glaring poor practices that could develop into bad habbits in the future.



    I know the standard way to solve this problem is just time = distance/(velA+velB), but what would the point of using objects be if i didnt have the objects do something and change their status in someway?



    what do you think, looks good?



    /*

    The goal for this practice program is to solve the common math word problem below using classes and objects.
    I feel that using iterations rather than the basic math formula to solve, although clearly less efficient, would be more true to thinking in terms of objects.

    Train A, traveling X miles per hour (mph), leaves Westford heading toward Eastford, 260 miles away.
    At the same time Train B, traveling Y mph, leaves Eastford heading toward Westford.
    When do the two trains meet? How far from each city do they meet?

    */

    #include "pch.h"
    #include <iostream>
    using namespace std;

    class Train

    public:
    Train(int, int);
    int getLocation();
    void update();
    private:
    int location, velocity;
    ;

    Train::Train(int loc, int vel) //to initialize the train object and set its location and velocity

    location = loc;
    velocity = vel;


    int Train::getLocation() // returns the location of the train object

    return location;


    void Train::update() // updates the train object for one iteration

    location += velocity;


    int main()

    int velA, velB, distance; //to take the values from the user input
    int time; // to keep track of the number of iterations
    // time is declared here so it can be used outside of the for loop


    //input
    cout << "Enter velocity of the train from Westford:n";
    cin >> velA;
    cout << "nnEnter velocity of the train from Eastford:n";
    cin >> velB;
    cout << "nnEnter the distance between Westford and Eastford:n";
    cin >> distance;

    //initialize each train
    Train trainA(0, velA);
    Train trainB(distance, 0 - velB); //location of trainB is distance because the distance between an x coordinate at 0 and another x coordinate is equal to the second x coordinate
    //the velocity of trainB is the negative of velB because it is traveling in the opposite direction of trainA

    //run the sim
    for (time = 0; trainA.getLocation() < trainB.getLocation(); time++)

    trainA.update();
    trainB.update();


    //output
    cout << "nnThe Trains pass eachother after " << time << " hours."
    << "nAt that time, the Westford train is " << trainA.getLocation() << " miles from Westfordn"
    << "and the Eastford train is " << distance - trainB.getLocation() << " miles from Eastford.nn";

    return 0;









    share







    New contributor




    Mickey Brenneman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$














      0












      0








      0





      $begingroup$


      Ive done a little bit of programming in the past, mostly just dabbling.
      After a long time of not touching an IDE, I am getting back into it. I just threw this quick project together to make sure I remember how to use classes and objects before I start playing with bigger projects.



      I would love a quick critique to make sure there arent any glaring poor practices that could develop into bad habbits in the future.



      I know the standard way to solve this problem is just time = distance/(velA+velB), but what would the point of using objects be if i didnt have the objects do something and change their status in someway?



      what do you think, looks good?



      /*

      The goal for this practice program is to solve the common math word problem below using classes and objects.
      I feel that using iterations rather than the basic math formula to solve, although clearly less efficient, would be more true to thinking in terms of objects.

      Train A, traveling X miles per hour (mph), leaves Westford heading toward Eastford, 260 miles away.
      At the same time Train B, traveling Y mph, leaves Eastford heading toward Westford.
      When do the two trains meet? How far from each city do they meet?

      */

      #include "pch.h"
      #include <iostream>
      using namespace std;

      class Train

      public:
      Train(int, int);
      int getLocation();
      void update();
      private:
      int location, velocity;
      ;

      Train::Train(int loc, int vel) //to initialize the train object and set its location and velocity

      location = loc;
      velocity = vel;


      int Train::getLocation() // returns the location of the train object

      return location;


      void Train::update() // updates the train object for one iteration

      location += velocity;


      int main()

      int velA, velB, distance; //to take the values from the user input
      int time; // to keep track of the number of iterations
      // time is declared here so it can be used outside of the for loop


      //input
      cout << "Enter velocity of the train from Westford:n";
      cin >> velA;
      cout << "nnEnter velocity of the train from Eastford:n";
      cin >> velB;
      cout << "nnEnter the distance between Westford and Eastford:n";
      cin >> distance;

      //initialize each train
      Train trainA(0, velA);
      Train trainB(distance, 0 - velB); //location of trainB is distance because the distance between an x coordinate at 0 and another x coordinate is equal to the second x coordinate
      //the velocity of trainB is the negative of velB because it is traveling in the opposite direction of trainA

      //run the sim
      for (time = 0; trainA.getLocation() < trainB.getLocation(); time++)

      trainA.update();
      trainB.update();


      //output
      cout << "nnThe Trains pass eachother after " << time << " hours."
      << "nAt that time, the Westford train is " << trainA.getLocation() << " miles from Westfordn"
      << "and the Eastford train is " << distance - trainB.getLocation() << " miles from Eastford.nn";

      return 0;









      share







      New contributor




      Mickey Brenneman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      Ive done a little bit of programming in the past, mostly just dabbling.
      After a long time of not touching an IDE, I am getting back into it. I just threw this quick project together to make sure I remember how to use classes and objects before I start playing with bigger projects.



      I would love a quick critique to make sure there arent any glaring poor practices that could develop into bad habbits in the future.



      I know the standard way to solve this problem is just time = distance/(velA+velB), but what would the point of using objects be if i didnt have the objects do something and change their status in someway?



      what do you think, looks good?



      /*

      The goal for this practice program is to solve the common math word problem below using classes and objects.
      I feel that using iterations rather than the basic math formula to solve, although clearly less efficient, would be more true to thinking in terms of objects.

      Train A, traveling X miles per hour (mph), leaves Westford heading toward Eastford, 260 miles away.
      At the same time Train B, traveling Y mph, leaves Eastford heading toward Westford.
      When do the two trains meet? How far from each city do they meet?

      */

      #include "pch.h"
      #include <iostream>
      using namespace std;

      class Train

      public:
      Train(int, int);
      int getLocation();
      void update();
      private:
      int location, velocity;
      ;

      Train::Train(int loc, int vel) //to initialize the train object and set its location and velocity

      location = loc;
      velocity = vel;


      int Train::getLocation() // returns the location of the train object

      return location;


      void Train::update() // updates the train object for one iteration

      location += velocity;


      int main()

      int velA, velB, distance; //to take the values from the user input
      int time; // to keep track of the number of iterations
      // time is declared here so it can be used outside of the for loop


      //input
      cout << "Enter velocity of the train from Westford:n";
      cin >> velA;
      cout << "nnEnter velocity of the train from Eastford:n";
      cin >> velB;
      cout << "nnEnter the distance between Westford and Eastford:n";
      cin >> distance;

      //initialize each train
      Train trainA(0, velA);
      Train trainB(distance, 0 - velB); //location of trainB is distance because the distance between an x coordinate at 0 and another x coordinate is equal to the second x coordinate
      //the velocity of trainB is the negative of velB because it is traveling in the opposite direction of trainA

      //run the sim
      for (time = 0; trainA.getLocation() < trainB.getLocation(); time++)

      trainA.update();
      trainB.update();


      //output
      cout << "nnThe Trains pass eachother after " << time << " hours."
      << "nAt that time, the Westford train is " << trainA.getLocation() << " miles from Westfordn"
      << "and the Eastford train is " << distance - trainB.getLocation() << " miles from Eastford.nn";

      return 0;







      c++17 visual-studio





      share







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      Mickey Brenneman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.










      share







      New contributor




      Mickey Brenneman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.








      share



      share






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      Mickey Brenneman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      asked 7 mins ago









      Mickey BrennemanMickey Brenneman

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      Check out our Code of Conduct.





      New contributor





      Mickey Brenneman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






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      Check out our Code of Conduct.




















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