Ttykuu

The goal is to reduce the run-time of the operation, the function is working as intended but I'm struggling to make it more efficient larger inputs

You are given 2 arguments:

possible_criminals = [['9AheT-12=', 'Daniel', 'Lenny', '3512-6910',
'134.0', 'USD', 'M53'],
['zOvfqFxTWqQ=', 'Sylar', 'Seil', '1081-6760', '331.0', 'GBP', 'A46047']]

personal_information = [['Tzhq+56p=', 'Daniel', 'Lenny', '134.0',
'USD','M53', '37'],
['qWNmZankudw=', 'Sylar', 'Seil', '331.0', 'GBP', 'A46047', '676']]

Return an output (as an array of strings) that checks the arguments against each other in the
following format:

scanner(possible_criminals, personal_information) =
[['9AheT-12=', 'Tzhq+56p=', 'criminal'], ['zOvfqFxTWqQ=', 'qWNmZankudw=',
'criminal']]

def scanner(possible_criminals , personal_information)

'''
this problem can be simplified by understanding that the output 
contains an array of 3 values
1) index[0] from argument 1
2) index[0] from argument 2
3) a value calculated by our function db_checker

steps to solve the problem:

- creating value 1) and 2) in output by extracting index 0 from given 
arguments(possible_criminals , personal_information)

- "prepare" the arguments(possible_criminals , personal_information) for comparison 
by sanitizing them:
 - run "".lower() to account for case-insensitive matches
 - pop unnecessary values

- calculating whether the arguments match by using a function
that compares possible_criminals with their personal_information
 - function checks how many matches are there
'''


 def db_checker(A, B):
 counter = 0
 for x in A:
 if B.count(x) == 0:
 counter += 1
 if counter == 0:
 return "criminal"
 elif counter == 1:
 return "possible"
 elif counter == 2:
 return "unlikely"
 else:
 return "none"

 def init_output(N, M):
 outputs = []
 for i in range(len(N)):
 output = []
 output += [N[i].pop(0)] + [M[i].pop(0)]
 outputs.append(output)
 N[i].pop(2) # remove undesired values
 M[i].pop(-1)
 N[i] = [y.lower() for y in N[i]]
 M[i] = [k.lower() for k in M[i]]
 return outputs, N, M

 # driver program
 final = init_output(possible_criminals , personal_information )

 for i in range(len(final[1])):
 final[0][i].append(confidence_calculator(final[1][i], final[2][i]))
 return final[0]

assert scanner(possible_criminals , personal_information) == 
[['9AheT-12=', 'Tzhq+56p=', 'criminal'], ['zOvfqFxTWqQ=', 'qWNmZankudw=', 'criminal']]