Unique Path problem with Robot Traversal in python

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Unique Path problem with Robot Traversal in python














0












$begingroup$


I got this problem during a mock interview, and I would like to get code review for the backtracking solution.




Robot Paths



from Leetcode https://leetcode.com/problems/unique-paths/description/



Prompt: Given a matrix of zeroes, determine how many unique paths exist



from the top left corner to the bottom right corner



#



Input: An Array of Array of Integers (matrix)



Output: Integer



#




# Example: matrix = [[0,0,0,0],
# [0,0,0,0],
# [0,0,0,0]]
#
# robotPaths(matrix) = 38
#
#
# matrix = [[0,0,0],
# [0,0,0]]
#
# robotPaths(matrix) = 4



# Note: From any point, you can travel in the four cardinal directions. I decided to do backtracking approach to solve this problem.
# (north, south, east, west). A path is valid as long as it travels
# from the top left corner to the bottom right corner, does not go
# off of the matrix, and does not travel back on itself


def robot_paths(matrix):
num_of_rows = len(matrix)
num_of_cols = len(matrix[0])

def traverse(row, col):
nonlocal num_of_rows
nonlocal num_of_cols
# is row and col inside the boundaries
if row < 0 or row >= num_of_rows or col < 0 or col >= num_of_cols:
return 0

# has row, col already been visited
if matrix[row][col] == 1:
return 0

# is row, col the destination?
if row == num_of_rows - 1 and col == num_of_cols - 1:
return 1

# mark coordinate as visited
matrix[row][col] = 1

# initialize sum of total unique paths to end from that coordinate
s = traverse(row, col + 1) + traverse(row + 1, col) + traverse(row - 1, col) + traverse(row, col - 1)

# backtrack; mark coordinate as unvisited so it can be
# used in another path
matrix[row][col] = 0

return s

return traverse(0, 0)








share









$endgroup$
















    0












    $begingroup$


    I got this problem during a mock interview, and I would like to get code review for the backtracking solution.




    Robot Paths



    from Leetcode https://leetcode.com/problems/unique-paths/description/



    Prompt: Given a matrix of zeroes, determine how many unique paths exist



    from the top left corner to the bottom right corner



    #



    Input: An Array of Array of Integers (matrix)



    Output: Integer



    #




    # Example: matrix = [[0,0,0,0],
    # [0,0,0,0],
    # [0,0,0,0]]
    #
    # robotPaths(matrix) = 38
    #
    #
    # matrix = [[0,0,0],
    # [0,0,0]]
    #
    # robotPaths(matrix) = 4



    # Note: From any point, you can travel in the four cardinal directions. I decided to do backtracking approach to solve this problem.
    # (north, south, east, west). A path is valid as long as it travels
    # from the top left corner to the bottom right corner, does not go
    # off of the matrix, and does not travel back on itself


    def robot_paths(matrix):
    num_of_rows = len(matrix)
    num_of_cols = len(matrix[0])

    def traverse(row, col):
    nonlocal num_of_rows
    nonlocal num_of_cols
    # is row and col inside the boundaries
    if row < 0 or row >= num_of_rows or col < 0 or col >= num_of_cols:
    return 0

    # has row, col already been visited
    if matrix[row][col] == 1:
    return 0

    # is row, col the destination?
    if row == num_of_rows - 1 and col == num_of_cols - 1:
    return 1

    # mark coordinate as visited
    matrix[row][col] = 1

    # initialize sum of total unique paths to end from that coordinate
    s = traverse(row, col + 1) + traverse(row + 1, col) + traverse(row - 1, col) + traverse(row, col - 1)

    # backtrack; mark coordinate as unvisited so it can be
    # used in another path
    matrix[row][col] = 0

    return s

    return traverse(0, 0)








    share









    $endgroup$














      0












      0








      0





      $begingroup$


      I got this problem during a mock interview, and I would like to get code review for the backtracking solution.




      Robot Paths



      from Leetcode https://leetcode.com/problems/unique-paths/description/



      Prompt: Given a matrix of zeroes, determine how many unique paths exist



      from the top left corner to the bottom right corner



      #



      Input: An Array of Array of Integers (matrix)



      Output: Integer



      #




      # Example: matrix = [[0,0,0,0],
      # [0,0,0,0],
      # [0,0,0,0]]
      #
      # robotPaths(matrix) = 38
      #
      #
      # matrix = [[0,0,0],
      # [0,0,0]]
      #
      # robotPaths(matrix) = 4



      # Note: From any point, you can travel in the four cardinal directions. I decided to do backtracking approach to solve this problem.
      # (north, south, east, west). A path is valid as long as it travels
      # from the top left corner to the bottom right corner, does not go
      # off of the matrix, and does not travel back on itself


      def robot_paths(matrix):
      num_of_rows = len(matrix)
      num_of_cols = len(matrix[0])

      def traverse(row, col):
      nonlocal num_of_rows
      nonlocal num_of_cols
      # is row and col inside the boundaries
      if row < 0 or row >= num_of_rows or col < 0 or col >= num_of_cols:
      return 0

      # has row, col already been visited
      if matrix[row][col] == 1:
      return 0

      # is row, col the destination?
      if row == num_of_rows - 1 and col == num_of_cols - 1:
      return 1

      # mark coordinate as visited
      matrix[row][col] = 1

      # initialize sum of total unique paths to end from that coordinate
      s = traverse(row, col + 1) + traverse(row + 1, col) + traverse(row - 1, col) + traverse(row, col - 1)

      # backtrack; mark coordinate as unvisited so it can be
      # used in another path
      matrix[row][col] = 0

      return s

      return traverse(0, 0)








      share









      $endgroup$




      I got this problem during a mock interview, and I would like to get code review for the backtracking solution.




      Robot Paths



      from Leetcode https://leetcode.com/problems/unique-paths/description/



      Prompt: Given a matrix of zeroes, determine how many unique paths exist



      from the top left corner to the bottom right corner



      #



      Input: An Array of Array of Integers (matrix)



      Output: Integer



      #




      # Example: matrix = [[0,0,0,0],
      # [0,0,0,0],
      # [0,0,0,0]]
      #
      # robotPaths(matrix) = 38
      #
      #
      # matrix = [[0,0,0],
      # [0,0,0]]
      #
      # robotPaths(matrix) = 4



      # Note: From any point, you can travel in the four cardinal directions. I decided to do backtracking approach to solve this problem.
      # (north, south, east, west). A path is valid as long as it travels
      # from the top left corner to the bottom right corner, does not go
      # off of the matrix, and does not travel back on itself


      def robot_paths(matrix):
      num_of_rows = len(matrix)
      num_of_cols = len(matrix[0])

      def traverse(row, col):
      nonlocal num_of_rows
      nonlocal num_of_cols
      # is row and col inside the boundaries
      if row < 0 or row >= num_of_rows or col < 0 or col >= num_of_cols:
      return 0

      # has row, col already been visited
      if matrix[row][col] == 1:
      return 0

      # is row, col the destination?
      if row == num_of_rows - 1 and col == num_of_cols - 1:
      return 1

      # mark coordinate as visited
      matrix[row][col] = 1

      # initialize sum of total unique paths to end from that coordinate
      s = traverse(row, col + 1) + traverse(row + 1, col) + traverse(row - 1, col) + traverse(row, col - 1)

      # backtrack; mark coordinate as unvisited so it can be
      # used in another path
      matrix[row][col] = 0

      return s

      return traverse(0, 0)






      backtracking





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      NinjaGNinjaG

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