Ttykuu

Please review and let me know which version is better?
Just trying to find any caveats or better ways to accomplish the a version comparison independent from android and ios.

Formats accepted: '1.0.0' or '1' formats and an operator, e.g: compareVersion('1', '1.2.0', '>')

export function compareVersion(version1, version2, operator) 
 const formattedV1 = version1.split(".");
 const formattedV2 = version2.split(".");

 let diff = 0;

 if (formattedV1.length !== formattedV2.length) 
 const lengthDiff = formattedV1.length - formattedV2.length;
 for (let index = 0; index < Math.abs(lengthDiff); index += 1) 
 if (lengthDiff > 0) 
 formattedV2.push("0");
 else 
 formattedV1.push("0");
 
 
 

 for (let index = 0; index < formattedV1.length; index += 1) 
 if (diff === 0) 
 const v1 = parseInt(formattedV1[index]);
 const v2 = parseInt(formattedV2[index]);
 if (isNaN(v1) 
 

 switch (operator) 
 case "=":
 case "==":
 return diff === 0;
 case ">=":
 return diff >= 0;
 case "<=":
 return diff <= 0;
 case ">":
 return diff > 0;
 case "<":
 return diff < 0;

 default:
 throw new Error("Problem comparing versions");
 
 

OR

export function compareVersions(a, b, operator) 
 const aParts = a.split('.');
 const bParts = b.split('.');

 const pairs = [];

 for (let index = 0; index < Math.max(aParts.length, bParts.length); index += 1) 
 pairs.push(
 a: parseInt(aParts[index]),
 b: parseInt(bParts[index]),
 );
 

 let diff = 0;

 pairs.forEach((pair) => 
 if (diff === 0) 
 if (pair.a > pair.b) 
 diff = 1;
 
 if (pair.b > pair.a) 
 diff = -1;
 
 if (!isNaN(pair.a) && isNaN(pair.b)) 
 diff = 1;
 
 if (isNaN(pair.a) && !isNaN(pair.b)) 
 diff = -1;
 
 
 );

 switch (operator) 
 case '=':
 case '==':
 return diff === 0;
 case '>=':
 return diff >= 0;
 case '<=':
 return diff <= 0;
 case '>':
 return diff > 0;
 case '<':
 return diff < 0;

 default:
 throw new Error('Problem comparing versions');