Project Euler # 1 python Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Project Euler Problem 12 in PythonFunction to return the sum of multiples within a rangeProject Euler 78: Coin Partitions in PythonProject Euler #14: Longest Collatz sequenceProject Euler #15 in PythonProject Euler #4 - Largest Palindrome Project - PythonProject Euler problem #1 in Python 3Sum of multiples of 3 or 5 using functional programmingProject Euler 001 in C++Project Euler Problem 37 in Python
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Project Euler # 1 python
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Project Euler Problem 12 in PythonFunction to return the sum of multiples within a rangeProject Euler 78: Coin Partitions in PythonProject Euler #14: Longest Collatz sequenceProject Euler #15 in PythonProject Euler #4 - Largest Palindrome Project - PythonProject Euler problem #1 in Python 3Sum of multiples of 3 or 5 using functional programmingProject Euler 001 in C++Project Euler Problem 37 in Python
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
$begingroup$
Prob.1 Sum of Multiples of 3 and 5 in range 1000.
def prob_1():
sum_mult=[] #Create an empty list which will take sum of multiples of 3 and 5
check_sum=0
for i in range(1,1000): #Take numbers till 1000
#if(i)
if( (i%3)==0 or (i%35)==0 ): #divisor condition
sum_mult.append(i)
return sum(sum_mult) #return sum of list
I am just starting out my journey as a programmer,here is my code and I would love to see any critical feedback and other alternative solutions maybe using some clever hack of using lambda function's etc.
performance python-3.x programming-challenge
New contributor
$endgroup$
add a comment |
$begingroup$
Prob.1 Sum of Multiples of 3 and 5 in range 1000.
def prob_1():
sum_mult=[] #Create an empty list which will take sum of multiples of 3 and 5
check_sum=0
for i in range(1,1000): #Take numbers till 1000
#if(i)
if( (i%3)==0 or (i%35)==0 ): #divisor condition
sum_mult.append(i)
return sum(sum_mult) #return sum of list
I am just starting out my journey as a programmer,here is my code and I would love to see any critical feedback and other alternative solutions maybe using some clever hack of using lambda function's etc.
performance python-3.x programming-challenge
New contributor
$endgroup$
add a comment |
$begingroup$
Prob.1 Sum of Multiples of 3 and 5 in range 1000.
def prob_1():
sum_mult=[] #Create an empty list which will take sum of multiples of 3 and 5
check_sum=0
for i in range(1,1000): #Take numbers till 1000
#if(i)
if( (i%3)==0 or (i%35)==0 ): #divisor condition
sum_mult.append(i)
return sum(sum_mult) #return sum of list
I am just starting out my journey as a programmer,here is my code and I would love to see any critical feedback and other alternative solutions maybe using some clever hack of using lambda function's etc.
performance python-3.x programming-challenge
New contributor
$endgroup$
Prob.1 Sum of Multiples of 3 and 5 in range 1000.
def prob_1():
sum_mult=[] #Create an empty list which will take sum of multiples of 3 and 5
check_sum=0
for i in range(1,1000): #Take numbers till 1000
#if(i)
if( (i%3)==0 or (i%35)==0 ): #divisor condition
sum_mult.append(i)
return sum(sum_mult) #return sum of list
I am just starting out my journey as a programmer,here is my code and I would love to see any critical feedback and other alternative solutions maybe using some clever hack of using lambda function's etc.
performance python-3.x programming-challenge
performance python-3.x programming-challenge
New contributor
New contributor
New contributor
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DjVasuDjVasu
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