Items also occurs in a set Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern) Announcing the arrival of Valued Associate #679: Cesar Manara Unicorn Meta Zoo #1: Why another podcast?Stone Game One FourHackerRank “Manasa and Stones” in PythonArranging words in sentences alphabeticallyThe Thirsty CrowHackerrank > Woman's CodeSprint 2 > stone division, Revisited ( recursive function)Hackerrank “Strings: Making Anagrams” Javascript SolutionStrings: Making AnagramsLeetCode “Jewels and Stones”: counting certain characters in a stringMr. Muffin's ball-passing gameSum of two numbers in array
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Items also occurs in a set
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)
Announcing the arrival of Valued Associate #679: Cesar Manara
Unicorn Meta Zoo #1: Why another podcast?Stone Game One FourHackerRank “Manasa and Stones” in PythonArranging words in sentences alphabeticallyThe Thirsty CrowHackerrank > Woman's CodeSprint 2 > stone division, Revisited ( recursive function)Hackerrank “Strings: Making Anagrams” Javascript SolutionStrings: Making AnagramsLeetCode “Jewels and Stones”: counting certain characters in a stringMr. Muffin's ball-passing gameSum of two numbers in array
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
$begingroup$
The task
You're given strings J representing the types of stones that are
jewels, and S representing the stones you have. Each character in S
is a type of stone you have. You want to know how many of the stones
you have are also jewels.
The letters in J are guaranteed distinct, and all characters in J and
S are letters. Letters are case sensitive, so "a" is considered a
different type of stone from "A".
Example 1:
Input: J = "aA", S = "aAAbbbb" Output: 3
Example 2:
Input: J = "z", S = "ZZ" Output: 0
Note:
S and J will consist of letters and have length at most 50. The
characters in J are distinct.
My functional solution
const findNumberOfJewels = (j,s) => [...s].reduce((num, x) => [...j].includes(x) ? num + 1 : num , 0);
console.log(findNumberOfJewels("aA", "aAAbbbb"));
My imperative solution
function findNumberOfJewels2(j,s)
let res = 0;
const set = new Set(j);
for (const x of s)
if (set.has(x)) ++res;
return res;
;
console.log(findNumberOfJewels2("aA", "aAAbbbb"));
javascript algorithm programming-challenge functional-programming ecmascript-6
asked 1 min ago
thadeuszlaythadeuszlay
997616
$endgroup$
add a comment |
$begingroup$
The task
You're given strings J representing the types of stones that are
jewels, and S representing the stones you have. Each character in S
is a type of stone you have. You want to know how many of the stones
you have are also jewels.
The letters in J are guaranteed distinct, and all characters in J and
S are letters. Letters are case sensitive, so "a" is considered a
different type of stone from "A".
Example 1:
Input: J = "aA", S = "aAAbbbb" Output: 3
Example 2:
Input: J = "z", S = "ZZ" Output: 0
Note:
S and J will consist of letters and have length at most 50. The
characters in J are distinct.
My functional solution
const findNumberOfJewels = (j,s) => [...s].reduce((num, x) => [...j].includes(x) ? num + 1 : num , 0);
console.log(findNumberOfJewels("aA", "aAAbbbb"));
My imperative solution
function findNumberOfJewels2(j,s)
let res = 0;
const set = new Set(j);
for (const x of s)
if (set.has(x)) ++res;
return res;
;
console.log(findNumberOfJewels2("aA", "aAAbbbb"));
javascript algorithm programming-challenge functional-programming ecmascript-6
asked 1 min ago
thadeuszlaythadeuszlay
997616
$endgroup$
add a comment |
$begingroup$
The task
You're given strings J representing the types of stones that are
jewels, and S representing the stones you have. Each character in S
is a type of stone you have. You want to know how many of the stones
you have are also jewels.
The letters in J are guaranteed distinct, and all characters in J and
S are letters. Letters are case sensitive, so "a" is considered a
different type of stone from "A".
Example 1:
Input: J = "aA", S = "aAAbbbb" Output: 3
Example 2:
Input: J = "z", S = "ZZ" Output: 0
Note:
S and J will consist of letters and have length at most 50. The
characters in J are distinct.
My functional solution
const findNumberOfJewels = (j,s) => [...s].reduce((num, x) => [...j].includes(x) ? num + 1 : num , 0);
console.log(findNumberOfJewels("aA", "aAAbbbb"));
My imperative solution
function findNumberOfJewels2(j,s)
let res = 0;
const set = new Set(j);
for (const x of s)
if (set.has(x)) ++res;
return res;
;
console.log(findNumberOfJewels2("aA", "aAAbbbb"));
javascript algorithm programming-challenge functional-programming ecmascript-6
asked 1 min ago
thadeuszlaythadeuszlay
997616
$endgroup$
The task
You're given strings J representing the types of stones that are
jewels, and S representing the stones you have. Each character in S
is a type of stone you have. You want to know how many of the stones
you have are also jewels.
The letters in J are guaranteed distinct, and all characters in J and
S are letters. Letters are case sensitive, so "a" is considered a
different type of stone from "A".
Example 1:
Input: J = "aA", S = "aAAbbbb" Output: 3
Example 2:
Input: J = "z", S = "ZZ" Output: 0
Note:
S and J will consist of letters and have length at most 50. The
characters in J are distinct.
My functional solution
const findNumberOfJewels = (j,s) => [...s].reduce((num, x) => [...j].includes(x) ? num + 1 : num , 0);
console.log(findNumberOfJewels("aA", "aAAbbbb"));
My imperative solution
function findNumberOfJewels2(j,s)
let res = 0;
const set = new Set(j);
for (const x of s)
if (set.has(x)) ++res;
return res;
;
console.log(findNumberOfJewels2("aA", "aAAbbbb"));
javascript algorithm programming-challenge functional-programming ecmascript-6
javascript algorithm programming-challenge functional-programming ecmascript-6
asked 1 min ago
thadeuszlaythadeuszlay
997616
asked 1 min ago
thadeuszlaythadeuszlay
997616
asked 1 min ago
thadeuszlaythadeuszlay
997616
asked 1 min ago
thadeuszlaythadeuszlay
997616
asked 1 min ago
thadeuszlaythadeuszlay
997616
997616
add a comment |
add a comment |
0
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