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Looping through a dictionary array



Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)
Announcing the arrival of Valued Associate #679: Cesar Manara
Unicorn Meta Zoo #1: Why another podcast?Improving performance when sorting array of structs by multiple fieldsSPOJ GENERAL: sorting by swaps of distance kPostponed Prime Sieve in SwiftCode for calculating best possible combination in an arrayBubble Sorting AlgorithmPrime Number Generator (6n + 1 or 6n - 1)Four sum algorithm mock interview practiceLeetcode 54: Spiral MatrixPerformance of stable marriage solution in Python 3Array Search Algorithm



.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








1












$begingroup$


I have the bellow algorithm which I wrote in order to loop through an dictionary array. which looks like: ["mediaX": AnyObject]



The problem is that sometimes, although it has only consistently happened with one post among hundreds, it will loop forever printing the error print statement. How could it be changed in order to make it more efficient or more safe?



for anyImage in snapshot! {

var mediaNumArrayOrderd = [Int]()

guard var imageUrlString = anyImage.value as? [String:AnyObject] else return
print("inside the anyImage22, ", imageUrlString)

var values = [AnyObject]()
var keys = [String]()
var Done = false
var j = 1

//The bellow algorithom sorts the array and stores the correct values to then loop through the above two arrays
while !Done
for i in imageUrlString

if "media(j)" == i.key
values.append(i.value)
keys.append(i.key)
print(i, " This is teh i for in if ")
if imageUrlString.count == j
Done = true
break;

j+=1
else
print("No,,.")
print("There was an error when sorting the medias. Line 136 in the p2 VC")
break



...//more code


Update:



Upon further testing, for some reason, all of a sudden all posts have this problem. i dont know why this is happening it seems to have come out of nowhere. Maybe it was a change elsewhere in the code, i will check but I think its unlikely.










share|improve this question









New contributor




NCT 127 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$


















    1












    $begingroup$


    I have the bellow algorithm which I wrote in order to loop through an dictionary array. which looks like: ["mediaX": AnyObject]



    The problem is that sometimes, although it has only consistently happened with one post among hundreds, it will loop forever printing the error print statement. How could it be changed in order to make it more efficient or more safe?



    for anyImage in snapshot! {

    var mediaNumArrayOrderd = [Int]()

    guard var imageUrlString = anyImage.value as? [String:AnyObject] else return
    print("inside the anyImage22, ", imageUrlString)

    var values = [AnyObject]()
    var keys = [String]()
    var Done = false
    var j = 1

    //The bellow algorithom sorts the array and stores the correct values to then loop through the above two arrays
    while !Done
    for i in imageUrlString

    if "media(j)" == i.key
    values.append(i.value)
    keys.append(i.key)
    print(i, " This is teh i for in if ")
    if imageUrlString.count == j
    Done = true
    break;

    j+=1
    else
    print("No,,.")
    print("There was an error when sorting the medias. Line 136 in the p2 VC")
    break



    ...//more code


    Update:



    Upon further testing, for some reason, all of a sudden all posts have this problem. i dont know why this is happening it seems to have come out of nowhere. Maybe it was a change elsewhere in the code, i will check but I think its unlikely.










    share|improve this question









    New contributor




    NCT 127 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$














      1












      1








      1


      1



      $begingroup$


      I have the bellow algorithm which I wrote in order to loop through an dictionary array. which looks like: ["mediaX": AnyObject]



      The problem is that sometimes, although it has only consistently happened with one post among hundreds, it will loop forever printing the error print statement. How could it be changed in order to make it more efficient or more safe?



      for anyImage in snapshot! {

      var mediaNumArrayOrderd = [Int]()

      guard var imageUrlString = anyImage.value as? [String:AnyObject] else return
      print("inside the anyImage22, ", imageUrlString)

      var values = [AnyObject]()
      var keys = [String]()
      var Done = false
      var j = 1

      //The bellow algorithom sorts the array and stores the correct values to then loop through the above two arrays
      while !Done
      for i in imageUrlString

      if "media(j)" == i.key
      values.append(i.value)
      keys.append(i.key)
      print(i, " This is teh i for in if ")
      if imageUrlString.count == j
      Done = true
      break;

      j+=1
      else
      print("No,,.")
      print("There was an error when sorting the medias. Line 136 in the p2 VC")
      break



      ...//more code


      Update:



      Upon further testing, for some reason, all of a sudden all posts have this problem. i dont know why this is happening it seems to have come out of nowhere. Maybe it was a change elsewhere in the code, i will check but I think its unlikely.










      share|improve this question









      New contributor




      NCT 127 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      I have the bellow algorithm which I wrote in order to loop through an dictionary array. which looks like: ["mediaX": AnyObject]



      The problem is that sometimes, although it has only consistently happened with one post among hundreds, it will loop forever printing the error print statement. How could it be changed in order to make it more efficient or more safe?



      for anyImage in snapshot! {

      var mediaNumArrayOrderd = [Int]()

      guard var imageUrlString = anyImage.value as? [String:AnyObject] else return
      print("inside the anyImage22, ", imageUrlString)

      var values = [AnyObject]()
      var keys = [String]()
      var Done = false
      var j = 1

      //The bellow algorithom sorts the array and stores the correct values to then loop through the above two arrays
      while !Done
      for i in imageUrlString

      if "media(j)" == i.key
      values.append(i.value)
      keys.append(i.key)
      print(i, " This is teh i for in if ")
      if imageUrlString.count == j
      Done = true
      break;

      j+=1
      else
      print("No,,.")
      print("There was an error when sorting the medias. Line 136 in the p2 VC")
      break



      ...//more code


      Update:



      Upon further testing, for some reason, all of a sudden all posts have this problem. i dont know why this is happening it seems to have come out of nowhere. Maybe it was a change elsewhere in the code, i will check but I think its unlikely.







      algorithm sorting swift ios






      share|improve this question









      New contributor




      NCT 127 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question









      New contributor




      NCT 127 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|improve this question




      share|improve this question








      edited 2 mins ago







      NCT 127













      New contributor




      NCT 127 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      asked 22 mins ago









      NCT 127NCT 127

      63




      63




      New contributor




      NCT 127 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.





      New contributor





      NCT 127 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      NCT 127 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.




















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