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Inversion Puzzle



The 2019 Stack Overflow Developer Survey Results Are InWhat is the cipher behind this circular cyphertext?A well balanced puzzle: Logic puzzle(s) in visual disguiseLepidopterology needed!Capture The StonesFind the number code in the pictureHow should the hexagon be coloured?The Alien grid of picturesA-maze-ing Navigation4x4 Sliding Puzzle with a twistASCII art troubles










4












$begingroup$


enter image description here



You can describe your inversions however you like. I think an ordered grid from the center (n,m) is easy to understand (doesn't matter where to start due to radial symmetry), or an image










share|improve this question







New contributor




Artem Lugin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$











  • $begingroup$
    Neat puzzle! Is there a reason why the black regions are not uniform? It's not important, but it makes the puzzle slightly harder to solve using an image editor because it breaks floodfilling.
    $endgroup$
    – noedne
    46 mins ago










  • $begingroup$
    Because I drew them in procreate. Thats a good point I'll remember that next time I make something like this
    $endgroup$
    – Artem Lugin
    42 mins ago















4












$begingroup$


enter image description here



You can describe your inversions however you like. I think an ordered grid from the center (n,m) is easy to understand (doesn't matter where to start due to radial symmetry), or an image










share|improve this question







New contributor




Artem Lugin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$











  • $begingroup$
    Neat puzzle! Is there a reason why the black regions are not uniform? It's not important, but it makes the puzzle slightly harder to solve using an image editor because it breaks floodfilling.
    $endgroup$
    – noedne
    46 mins ago










  • $begingroup$
    Because I drew them in procreate. Thats a good point I'll remember that next time I make something like this
    $endgroup$
    – Artem Lugin
    42 mins ago













4












4








4





$begingroup$


enter image description here



You can describe your inversions however you like. I think an ordered grid from the center (n,m) is easy to understand (doesn't matter where to start due to radial symmetry), or an image










share|improve this question







New contributor




Artem Lugin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




enter image description here



You can describe your inversions however you like. I think an ordered grid from the center (n,m) is easy to understand (doesn't matter where to start due to radial symmetry), or an image







visual






share|improve this question







New contributor




Artem Lugin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question







New contributor




Artem Lugin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question






New contributor




Artem Lugin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 1 hour ago









Artem LuginArtem Lugin

736




736




New contributor




Artem Lugin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Artem Lugin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Artem Lugin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











  • $begingroup$
    Neat puzzle! Is there a reason why the black regions are not uniform? It's not important, but it makes the puzzle slightly harder to solve using an image editor because it breaks floodfilling.
    $endgroup$
    – noedne
    46 mins ago










  • $begingroup$
    Because I drew them in procreate. Thats a good point I'll remember that next time I make something like this
    $endgroup$
    – Artem Lugin
    42 mins ago
















  • $begingroup$
    Neat puzzle! Is there a reason why the black regions are not uniform? It's not important, but it makes the puzzle slightly harder to solve using an image editor because it breaks floodfilling.
    $endgroup$
    – noedne
    46 mins ago










  • $begingroup$
    Because I drew them in procreate. Thats a good point I'll remember that next time I make something like this
    $endgroup$
    – Artem Lugin
    42 mins ago















$begingroup$
Neat puzzle! Is there a reason why the black regions are not uniform? It's not important, but it makes the puzzle slightly harder to solve using an image editor because it breaks floodfilling.
$endgroup$
– noedne
46 mins ago




$begingroup$
Neat puzzle! Is there a reason why the black regions are not uniform? It's not important, but it makes the puzzle slightly harder to solve using an image editor because it breaks floodfilling.
$endgroup$
– noedne
46 mins ago












$begingroup$
Because I drew them in procreate. Thats a good point I'll remember that next time I make something like this
$endgroup$
– Artem Lugin
42 mins ago




$begingroup$
Because I drew them in procreate. Thats a good point I'll remember that next time I make something like this
$endgroup$
– Artem Lugin
42 mins ago










2 Answers
2






active

oldest

votes


















2












$begingroup$

My solution is




2 moves to make the inversions - was very slow to make this horrible graphic!
enter image description here







share|improve this answer











$endgroup$




















    2












    $begingroup$

    EDIT: I found an even better




    2 inversion solution:


    And of course, this is the optimal solution because you obviously can’t get to the end with only one inversion




    Original answer: I can do it in




    6 inversions




    by




    inverting a set of 4 non-adjacent big triangles (the ones that go BWBW or WBWB), then inverting the 2 black rings that result from that. (Will update with a visual later)







    share|improve this answer











    $endgroup$












    • $begingroup$
      Thanks for helping me out @Adam!
      $endgroup$
      – PiIsNot3
      5 mins ago











    Your Answer





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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    2












    $begingroup$

    My solution is




    2 moves to make the inversions - was very slow to make this horrible graphic!
    enter image description here







    share|improve this answer











    $endgroup$

















      2












      $begingroup$

      My solution is




      2 moves to make the inversions - was very slow to make this horrible graphic!
      enter image description here







      share|improve this answer











      $endgroup$















        2












        2








        2





        $begingroup$

        My solution is




        2 moves to make the inversions - was very slow to make this horrible graphic!
        enter image description here







        share|improve this answer











        $endgroup$



        My solution is




        2 moves to make the inversions - was very slow to make this horrible graphic!
        enter image description here








        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited 13 mins ago

























        answered 32 mins ago









        Weather VaneWeather Vane

        2,137112




        2,137112





















            2












            $begingroup$

            EDIT: I found an even better




            2 inversion solution:


            And of course, this is the optimal solution because you obviously can’t get to the end with only one inversion




            Original answer: I can do it in




            6 inversions




            by




            inverting a set of 4 non-adjacent big triangles (the ones that go BWBW or WBWB), then inverting the 2 black rings that result from that. (Will update with a visual later)







            share|improve this answer











            $endgroup$












            • $begingroup$
              Thanks for helping me out @Adam!
              $endgroup$
              – PiIsNot3
              5 mins ago















            2












            $begingroup$

            EDIT: I found an even better




            2 inversion solution:


            And of course, this is the optimal solution because you obviously can’t get to the end with only one inversion




            Original answer: I can do it in




            6 inversions




            by




            inverting a set of 4 non-adjacent big triangles (the ones that go BWBW or WBWB), then inverting the 2 black rings that result from that. (Will update with a visual later)







            share|improve this answer











            $endgroup$












            • $begingroup$
              Thanks for helping me out @Adam!
              $endgroup$
              – PiIsNot3
              5 mins ago













            2












            2








            2





            $begingroup$

            EDIT: I found an even better




            2 inversion solution:


            And of course, this is the optimal solution because you obviously can’t get to the end with only one inversion




            Original answer: I can do it in




            6 inversions




            by




            inverting a set of 4 non-adjacent big triangles (the ones that go BWBW or WBWB), then inverting the 2 black rings that result from that. (Will update with a visual later)







            share|improve this answer











            $endgroup$



            EDIT: I found an even better




            2 inversion solution:


            And of course, this is the optimal solution because you obviously can’t get to the end with only one inversion




            Original answer: I can do it in




            6 inversions




            by




            inverting a set of 4 non-adjacent big triangles (the ones that go BWBW or WBWB), then inverting the 2 black rings that result from that. (Will update with a visual later)








            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited 6 mins ago









            Adam

            333120




            333120










            answered 56 mins ago









            PiIsNot3PiIsNot3

            2,140330




            2,140330











            • $begingroup$
              Thanks for helping me out @Adam!
              $endgroup$
              – PiIsNot3
              5 mins ago
















            • $begingroup$
              Thanks for helping me out @Adam!
              $endgroup$
              – PiIsNot3
              5 mins ago















            $begingroup$
            Thanks for helping me out @Adam!
            $endgroup$
            – PiIsNot3
            5 mins ago




            $begingroup$
            Thanks for helping me out @Adam!
            $endgroup$
            – PiIsNot3
            5 mins ago










            Artem Lugin is a new contributor. Be nice, and check out our Code of Conduct.









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