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$begingroup$

I am reading the "You Don't Know JavaScript" series of books by Kyle Simpson and I am really enjoying it so far, it is so deep and full of JavaScript tips and tricks. I stumbled upon a closure section and I am unable to understand this code properly:

for (var i=1; i<=5; i++) 
setTimeout( function timer()
console.log( i );
, i*1000 );

As the author says most developers would assume that the numbers from 1 to 5 are printed but what happens is that 6 is printed 5 times in the console.

What I am struggling to understand is why the function that includes the timeout/timer is only executed after the loop is finished and not executed during the iteration of the i variable?

The setTimeout function is nested inside the for loop, but it's only executed after the for loop is finished 5 times! The author also mentions that even if the timeout was 0, the behavior would be the same. I hope someone can explain, as I am all new to this.

javascript

share

asked 9 mins ago

Arto KalishianArto Kalishian

1

New contributor

Arto Kalishian is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

add a comment | 

0

$begingroup$

I am reading the "You Don't Know JavaScript" series of books by Kyle Simpson and I am really enjoying it so far, it is so deep and full of JavaScript tips and tricks. I stumbled upon a closure section and I am unable to understand this code properly:

for (var i=1; i<=5; i++) 
setTimeout( function timer()
console.log( i );
, i*1000 );

As the author says most developers would assume that the numbers from 1 to 5 are printed but what happens is that 6 is printed 5 times in the console.

What I am struggling to understand is why the function that includes the timeout/timer is only executed after the loop is finished and not executed during the iteration of the i variable?

The setTimeout function is nested inside the for loop, but it's only executed after the for loop is finished 5 times! The author also mentions that even if the timeout was 0, the behavior would be the same. I hope someone can explain, as I am all new to this.

javascript

share

asked 9 mins ago

Arto KalishianArto Kalishian

1

New contributor

Arto Kalishian is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

add a comment | 

$begingroup$

I am reading the "You Don't Know JavaScript" series of books by Kyle Simpson and I am really enjoying it so far, it is so deep and full of JavaScript tips and tricks. I stumbled upon a closure section and I am unable to understand this code properly:

for (var i=1; i<=5; i++) 
setTimeout( function timer()
console.log( i );
, i*1000 );

As the author says most developers would assume that the numbers from 1 to 5 are printed but what happens is that 6 is printed 5 times in the console.

What I am struggling to understand is why the function that includes the timeout/timer is only executed after the loop is finished and not executed during the iteration of the i variable?

The setTimeout function is nested inside the for loop, but it's only executed after the for loop is finished 5 times! The author also mentions that even if the timeout was 0, the behavior would be the same. I hope someone can explain, as I am all new to this.

javascript

share

asked 9 mins ago

Arto KalishianArto Kalishian

1

New contributor

Arto Kalishian is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

for (var i=1; i<=5; i++) 
setTimeout( function timer()
console.log( i );
, i*1000 );

share

asked 9 mins ago

Arto KalishianArto Kalishian

1

New contributor

Arto Kalishian is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share

asked 9 mins ago

Arto KalishianArto Kalishian

1

New contributor

Arto Kalishian is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 9 mins ago

Arto KalishianArto Kalishian

1

New contributor

Arto Kalishian is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 9 mins ago

Arto KalishianArto Kalishian

1