Write a program that prints the longest substring in which the letters occur in alphabetical order by asciiPangrams CodeEval challengeImproving efficiency for finding longest contiguous non-decreasing substringLongest Palindromic SubstringFinding longest common prefixFinding the longest substring in alphabetical orderPython program to check substring match locations with a lot of permutations of the substringLongest substring in alphabetical orderA program that prints the longest substring of s in which the letters occur in alphabetical orderBalancedPassword Codility taskFind the longest word in set D that is a subsequence of string S
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Write a program that prints the longest substring in which the letters occur in alphabetical order by ascii
Pangrams CodeEval challengeImproving efficiency for finding longest contiguous non-decreasing substringLongest Palindromic SubstringFinding longest common prefixFinding the longest substring in alphabetical orderPython program to check substring match locations with a lot of permutations of the substringLongest substring in alphabetical orderA program that prints the longest substring of s in which the letters occur in alphabetical orderBalancedPassword Codility taskFind the longest word in set D that is a subsequence of string S
$begingroup$
Write a program that prints the longest substring of s in which the letters occur in alphabetical order. And the output has to be: Longest substring in alphabetical order is: beggh
here is my code. How can I get an output? Help Please, thanks :)
s = 'azcbobobegghakl'
characters = ""
for num in range(len(s)):
if num == len(s) - 1:
break
elif ord(s[num]) <= ord(s[num + 1]):
characters += s[num]
elif ord(s[num]) >= ord(s[num - 1]):
characters += s[num]
python
New contributor
Sergei Bykovskiy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Write a program that prints the longest substring of s in which the letters occur in alphabetical order. And the output has to be: Longest substring in alphabetical order is: beggh
here is my code. How can I get an output? Help Please, thanks :)
s = 'azcbobobegghakl'
characters = ""
for num in range(len(s)):
if num == len(s) - 1:
break
elif ord(s[num]) <= ord(s[num + 1]):
characters += s[num]
elif ord(s[num]) >= ord(s[num - 1]):
characters += s[num]
python
New contributor
Sergei Bykovskiy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Write a program that prints the longest substring of s in which the letters occur in alphabetical order. And the output has to be: Longest substring in alphabetical order is: beggh
here is my code. How can I get an output? Help Please, thanks :)
s = 'azcbobobegghakl'
characters = ""
for num in range(len(s)):
if num == len(s) - 1:
break
elif ord(s[num]) <= ord(s[num + 1]):
characters += s[num]
elif ord(s[num]) >= ord(s[num - 1]):
characters += s[num]
python
New contributor
Sergei Bykovskiy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
Write a program that prints the longest substring of s in which the letters occur in alphabetical order. And the output has to be: Longest substring in alphabetical order is: beggh
here is my code. How can I get an output? Help Please, thanks :)
s = 'azcbobobegghakl'
characters = ""
for num in range(len(s)):
if num == len(s) - 1:
break
elif ord(s[num]) <= ord(s[num + 1]):
characters += s[num]
elif ord(s[num]) >= ord(s[num - 1]):
characters += s[num]
python
python
New contributor
Sergei Bykovskiy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Sergei Bykovskiy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 1 hour ago
Sergei Bykovskiy
New contributor
Sergei Bykovskiy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 1 hour ago
Sergei BykovskiySergei Bykovskiy
11
11
New contributor
Sergei Bykovskiy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Sergei Bykovskiy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Sergei Bykovskiy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
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