How to exclude some combination of itertools.product?
Is it possible to upcast ritual spells?
What is a ^ b and (a & b) << 1?
What options are left, if Britain cannot decide?
Do the common programs (for example: "ls", "cat") in Linux and BSD come from the same source code?
ERC721: How to get the owned tokens of an address
Can I use USB data pins as power source
Instead of a Universal Basic Income program, why not implement a "Universal Basic Needs" program?
Is a party consisting of only a bard, a cleric, and a warlock functional long-term?
How could an airship be repaired midflight?
Recruiter wants very extensive technical details about all of my previous work
Does this sum go infinity?
Is it true that good novels will automatically sell themselves on Amazon (and so on) and there is no need for one to waste time promoting?
New passport but visa is in old (lost) passport
Shortcut for setting origin to vertex
I am confused as to how the inverse of a certain function is found.
Fastest way to pop N items from a large dict
Are all passive ability checks floors for active ability checks?
This word with a lot of past tenses
Professor being mistaken for a grad student
Is honey really a supersaturated solution? Does heating to un-crystalize redissolve it or melt it?
Print a physical multiplication table
Why do passenger jet manufacturers design their planes with stall prevention systems?
Welcoming 2019 Pi day: How to draw the letter π?
Why does overlay work only on the first tcolorbox?
How to exclude some combination of itertools.product?
0
$begingroup$
I have such set of data:
params =
'child': ['sasha','masha','baby'],
'action': ['play','cry'],
'lesson': ['mathematica','lingvo']
I use itertools.product such a way:
keys, values = zip(*params.items())
for v in itertools.product(*values):
event = dict(zip(keys, v))
pprint(event)
which is results:
'action': 'play', 'child': 'sasha', 'lesson': 'mathematica'
'action': 'play', 'child': 'sasha', 'lesson': 'lingvo'
'action': 'cry', 'child': 'sasha', 'lesson': 'mathematica'
'action': 'cry', 'child': 'sasha', 'lesson': 'lingvo'
'action': 'play', 'child': 'masha', 'lesson': 'mathematica'
'action': 'play', 'child': 'masha', 'lesson': 'lingvo'
'action': 'cry', 'child': 'masha', 'lesson': 'mathematica'
'action': 'cry', 'child': 'masha', 'lesson': 'lingvo'
'action': 'play', 'child': 'baby', 'lesson': 'mathematica'
'action': 'play', 'child': 'baby', 'lesson': 'lingvo'
'action': 'cry', 'child': 'baby', 'lesson': 'mathematica'
'action': 'cry', 'child': 'baby', 'lesson': 'lingvo'
But I don't need combination child=baby with any value of lesson
What is the elegant way to produce:
'action': 'play', 'child': 'sasha', 'lesson': 'mathematica'
'action': 'play', 'child': 'sasha', 'lesson': 'lingvo'
'action': 'cry', 'child': 'sasha', 'lesson': 'mathematica'
'action': 'cry', 'child': 'sasha', 'lesson': 'lingvo'
'action': 'play', 'child': 'masha', 'lesson': 'mathematica'
'action': 'play', 'child': 'masha', 'lesson': 'lingvo'
'action': 'cry', 'child': 'masha', 'lesson': 'mathematica'
'action': 'cry', 'child': 'masha', 'lesson': 'lingvo'
'action': 'play', 'child': 'baby'
'action': 'cry', 'child': 'baby'
?
python combinatorics
asked 4 mins ago
Александр КоролёвАлександр Королёв
1
New contributor
Александр Королёв is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
0
$begingroup$
I have such set of data:
params =
'child': ['sasha','masha','baby'],
'action': ['play','cry'],
'lesson': ['mathematica','lingvo']
I use itertools.product such a way:
keys, values = zip(*params.items())
for v in itertools.product(*values):
event = dict(zip(keys, v))
pprint(event)
which is results:
'action': 'play', 'child': 'sasha', 'lesson': 'mathematica'
'action': 'play', 'child': 'sasha', 'lesson': 'lingvo'
'action': 'cry', 'child': 'sasha', 'lesson': 'mathematica'
'action': 'cry', 'child': 'sasha', 'lesson': 'lingvo'
'action': 'play', 'child': 'masha', 'lesson': 'mathematica'
'action': 'play', 'child': 'masha', 'lesson': 'lingvo'
'action': 'cry', 'child': 'masha', 'lesson': 'mathematica'
'action': 'cry', 'child': 'masha', 'lesson': 'lingvo'
'action': 'play', 'child': 'baby', 'lesson': 'mathematica'
'action': 'play', 'child': 'baby', 'lesson': 'lingvo'
'action': 'cry', 'child': 'baby', 'lesson': 'mathematica'
'action': 'cry', 'child': 'baby', 'lesson': 'lingvo'
But I don't need combination child=baby with any value of lesson
What is the elegant way to produce:
'action': 'play', 'child': 'sasha', 'lesson': 'mathematica'
'action': 'play', 'child': 'sasha', 'lesson': 'lingvo'
'action': 'cry', 'child': 'sasha', 'lesson': 'mathematica'
'action': 'cry', 'child': 'sasha', 'lesson': 'lingvo'
'action': 'play', 'child': 'masha', 'lesson': 'mathematica'
'action': 'play', 'child': 'masha', 'lesson': 'lingvo'
'action': 'cry', 'child': 'masha', 'lesson': 'mathematica'
'action': 'cry', 'child': 'masha', 'lesson': 'lingvo'
'action': 'play', 'child': 'baby'
'action': 'cry', 'child': 'baby'
?
python combinatorics
asked 4 mins ago
Александр КоролёвАлександр Королёв
1
New contributor
Александр Королёв is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
0
0
0
$begingroup$
I have such set of data:
params =
'child': ['sasha','masha','baby'],
'action': ['play','cry'],
'lesson': ['mathematica','lingvo']
I use itertools.product such a way:
keys, values = zip(*params.items())
for v in itertools.product(*values):
event = dict(zip(keys, v))
pprint(event)
which is results:
'action': 'play', 'child': 'sasha', 'lesson': 'mathematica'
'action': 'play', 'child': 'sasha', 'lesson': 'lingvo'
'action': 'cry', 'child': 'sasha', 'lesson': 'mathematica'
'action': 'cry', 'child': 'sasha', 'lesson': 'lingvo'
'action': 'play', 'child': 'masha', 'lesson': 'mathematica'
'action': 'play', 'child': 'masha', 'lesson': 'lingvo'
'action': 'cry', 'child': 'masha', 'lesson': 'mathematica'
'action': 'cry', 'child': 'masha', 'lesson': 'lingvo'
'action': 'play', 'child': 'baby', 'lesson': 'mathematica'
'action': 'play', 'child': 'baby', 'lesson': 'lingvo'
'action': 'cry', 'child': 'baby', 'lesson': 'mathematica'
'action': 'cry', 'child': 'baby', 'lesson': 'lingvo'
But I don't need combination child=baby with any value of lesson
What is the elegant way to produce:
'action': 'play', 'child': 'sasha', 'lesson': 'mathematica'
'action': 'play', 'child': 'sasha', 'lesson': 'lingvo'
'action': 'cry', 'child': 'sasha', 'lesson': 'mathematica'
'action': 'cry', 'child': 'sasha', 'lesson': 'lingvo'
'action': 'play', 'child': 'masha', 'lesson': 'mathematica'
'action': 'play', 'child': 'masha', 'lesson': 'lingvo'
'action': 'cry', 'child': 'masha', 'lesson': 'mathematica'
'action': 'cry', 'child': 'masha', 'lesson': 'lingvo'
'action': 'play', 'child': 'baby'
'action': 'cry', 'child': 'baby'
?
python combinatorics
asked 4 mins ago
Александр КоролёвАлександр Королёв
1
New contributor
Александр Королёв is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I have such set of data:
params =
'child': ['sasha','masha','baby'],
'action': ['play','cry'],
'lesson': ['mathematica','lingvo']
I use itertools.product such a way:
keys, values = zip(*params.items())
for v in itertools.product(*values):
event = dict(zip(keys, v))
pprint(event)
which is results:
'action': 'play', 'child': 'sasha', 'lesson': 'mathematica'
'action': 'play', 'child': 'sasha', 'lesson': 'lingvo'
'action': 'cry', 'child': 'sasha', 'lesson': 'mathematica'
'action': 'cry', 'child': 'sasha', 'lesson': 'lingvo'
'action': 'play', 'child': 'masha', 'lesson': 'mathematica'
'action': 'play', 'child': 'masha', 'lesson': 'lingvo'
'action': 'cry', 'child': 'masha', 'lesson': 'mathematica'
'action': 'cry', 'child': 'masha', 'lesson': 'lingvo'
'action': 'play', 'child': 'baby', 'lesson': 'mathematica'
'action': 'play', 'child': 'baby', 'lesson': 'lingvo'
'action': 'cry', 'child': 'baby', 'lesson': 'mathematica'
'action': 'cry', 'child': 'baby', 'lesson': 'lingvo'
But I don't need combination child=baby with any value of lesson
What is the elegant way to produce:
'action': 'play', 'child': 'sasha', 'lesson': 'mathematica'
'action': 'play', 'child': 'sasha', 'lesson': 'lingvo'
'action': 'cry', 'child': 'sasha', 'lesson': 'mathematica'
'action': 'cry', 'child': 'sasha', 'lesson': 'lingvo'
'action': 'play', 'child': 'masha', 'lesson': 'mathematica'
'action': 'play', 'child': 'masha', 'lesson': 'lingvo'
'action': 'cry', 'child': 'masha', 'lesson': 'mathematica'
'action': 'cry', 'child': 'masha', 'lesson': 'lingvo'
'action': 'play', 'child': 'baby'
'action': 'cry', 'child': 'baby'
?
python combinatorics
python combinatorics
asked 4 mins ago
Александр КоролёвАлександр Королёв
1
New contributor
Александр Королёв is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 4 mins ago
Александр КоролёвАлександр Королёв
1
New contributor
Александр Королёв is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 4 mins ago
Александр КоролёвАлександр Королёв
1
New contributor
Александр Королёв is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 4 mins ago
Александр КоролёвАлександр Королёв
1
asked 4 mins ago
Александр КоролёвАлександр Королёв
1
1
New contributor
Александр Королёв is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Александр Королёв is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Александр Королёв is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function ()
return StackExchange.using("mathjaxEditing", function ()
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["\$", "\$"]]);
);
);
, "mathjax-editing");
StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "196"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Александр Королёв is a new contributor. Be nice, and check out our Code of Conduct.
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
var $window = $(window),
onScroll = function(e)
var $elem = $('.new-login-left'),
docViewTop = $window.scrollTop(),
docViewBottom = docViewTop + $window.height(),
elemTop = $elem.offset().top,
elemBottom = elemTop + $elem.height();
if ((docViewTop elemBottom))
StackExchange.using('gps', function() StackExchange.gps.track('embedded_signup_form.view', location: 'question_page' ); );
$window.unbind('scroll', onScroll);
;
$window.on('scroll', onScroll);
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f215582%2fhow-to-exclude-some-combination-of-itertools-product%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Александр Королёв is a new contributor. Be nice, and check out our Code of Conduct.
draft saved
draft discarded
Александр Королёв is a new contributor. Be nice, and check out our Code of Conduct.
Александр Королёв is a new contributor. Be nice, and check out our Code of Conduct.
Александр Королёв is a new contributor. Be nice, and check out our Code of Conduct.
Thanks for contributing an answer to Code Review Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
var $window = $(window),
onScroll = function(e)
var $elem = $('.new-login-left'),
docViewTop = $window.scrollTop(),
docViewBottom = docViewTop + $window.height(),
elemTop = $elem.offset().top,
elemBottom = elemTop + $elem.height();
if ((docViewTop elemBottom))
StackExchange.using('gps', function() StackExchange.gps.track('embedded_signup_form.view', location: 'question_page' ); );
$window.unbind('scroll', onScroll);
;
$window.on('scroll', onScroll);
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f215582%2fhow-to-exclude-some-combination-of-itertools-product%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
var $window = $(window),
onScroll = function(e)
var $elem = $('.new-login-left'),
docViewTop = $window.scrollTop(),
docViewBottom = docViewTop + $window.height(),
elemTop = $elem.offset().top,
elemBottom = elemTop + $elem.height();
if ((docViewTop elemBottom))
StackExchange.using('gps', function() StackExchange.gps.track('embedded_signup_form.view', location: 'question_page' ); );
$window.unbind('scroll', onScroll);
;
$window.on('scroll', onScroll);
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
var $window = $(window),
onScroll = function(e)
var $elem = $('.new-login-left'),
docViewTop = $window.scrollTop(),
docViewBottom = docViewTop + $window.height(),
elemTop = $elem.offset().top,
elemBottom = elemTop + $elem.height();
if ((docViewTop elemBottom))
StackExchange.using('gps', function() StackExchange.gps.track('embedded_signup_form.view', location: 'question_page' ); );
$window.unbind('scroll', onScroll);
;
$window.on('scroll', onScroll);
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
var $window = $(window),
onScroll = function(e)
var $elem = $('.new-login-left'),
docViewTop = $window.scrollTop(),
docViewBottom = docViewTop + $window.height(),
elemTop = $elem.offset().top,
elemBottom = elemTop + $elem.height();
if ((docViewTop elemBottom))
StackExchange.using('gps', function() StackExchange.gps.track('embedded_signup_form.view', location: 'question_page' ); );
$window.unbind('scroll', onScroll);
;
$window.on('scroll', onScroll);
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
