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Divide an array into two parts


Racing Java Arrays.sort with NON recursive Merge Sort implementationPerforming several integer division operations on an arrayHackerrank's Sherlock and ArrayLeetCode Rotate ArrayFinding an equilibrium index in an int arrayCode that prints ASCII bowties to screen given inputsRearranging an array such that positive and negative elements are at alternate positions“Ease the Array” challengeSort an array of 0s, 1s and 2s in JavaSubset Sums in Java













0












$begingroup$


I am trying to divide an array into 2 equal parts. below code is working fine as given input ->> int arr[] = 1,2,3,4,5,6,7,8,9,10; for even number of array elements but in odd number of input elements.



Q1 - One index is missing when inputs are odd (Size of array is odd).



Q2 - I want to improve complexity of this program



public class DivideArray 
public static void main(String[] args)
int arr[] = 1,2,3,4,5,6,7,8,9,10;
int len = arr.length;
int arr1[]= new int[(len/2)+1];
int arr2[] = new int[(len/2)+1];
for(int i=0;i<arr.length;i++)
if(((len/2))>i)
arr1[i] = arr[i];

else
arr2[(arr.length-i)-1] = arr[i];


//First half array
System.out.println("First half array");
for(int i=0;i<arr.length/2;i++)
System.out.print(" " + arr1[i]);

//Second half array
System.out.println();
System.out.println("Second half array");
for(int i=arr.length/2-1;i>=0;i--)
System.out.print(" " + arr2[i]);











share







New contributor




Ved Prakash is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$











  • $begingroup$
    Please explain this arr2[(arr.length-i)-1] = arr[i];
    $endgroup$
    – Mukul Kumar
    1 min ago















0












$begingroup$


I am trying to divide an array into 2 equal parts. below code is working fine as given input ->> int arr[] = 1,2,3,4,5,6,7,8,9,10; for even number of array elements but in odd number of input elements.



Q1 - One index is missing when inputs are odd (Size of array is odd).



Q2 - I want to improve complexity of this program



public class DivideArray 
public static void main(String[] args)
int arr[] = 1,2,3,4,5,6,7,8,9,10;
int len = arr.length;
int arr1[]= new int[(len/2)+1];
int arr2[] = new int[(len/2)+1];
for(int i=0;i<arr.length;i++)
if(((len/2))>i)
arr1[i] = arr[i];

else
arr2[(arr.length-i)-1] = arr[i];


//First half array
System.out.println("First half array");
for(int i=0;i<arr.length/2;i++)
System.out.print(" " + arr1[i]);

//Second half array
System.out.println();
System.out.println("Second half array");
for(int i=arr.length/2-1;i>=0;i--)
System.out.print(" " + arr2[i]);











share







New contributor




Ved Prakash is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$











  • $begingroup$
    Please explain this arr2[(arr.length-i)-1] = arr[i];
    $endgroup$
    – Mukul Kumar
    1 min ago













0












0








0





$begingroup$


I am trying to divide an array into 2 equal parts. below code is working fine as given input ->> int arr[] = 1,2,3,4,5,6,7,8,9,10; for even number of array elements but in odd number of input elements.



Q1 - One index is missing when inputs are odd (Size of array is odd).



Q2 - I want to improve complexity of this program



public class DivideArray 
public static void main(String[] args)
int arr[] = 1,2,3,4,5,6,7,8,9,10;
int len = arr.length;
int arr1[]= new int[(len/2)+1];
int arr2[] = new int[(len/2)+1];
for(int i=0;i<arr.length;i++)
if(((len/2))>i)
arr1[i] = arr[i];

else
arr2[(arr.length-i)-1] = arr[i];


//First half array
System.out.println("First half array");
for(int i=0;i<arr.length/2;i++)
System.out.print(" " + arr1[i]);

//Second half array
System.out.println();
System.out.println("Second half array");
for(int i=arr.length/2-1;i>=0;i--)
System.out.print(" " + arr2[i]);











share







New contributor




Ved Prakash is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




I am trying to divide an array into 2 equal parts. below code is working fine as given input ->> int arr[] = 1,2,3,4,5,6,7,8,9,10; for even number of array elements but in odd number of input elements.



Q1 - One index is missing when inputs are odd (Size of array is odd).



Q2 - I want to improve complexity of this program



public class DivideArray 
public static void main(String[] args)
int arr[] = 1,2,3,4,5,6,7,8,9,10;
int len = arr.length;
int arr1[]= new int[(len/2)+1];
int arr2[] = new int[(len/2)+1];
for(int i=0;i<arr.length;i++)
if(((len/2))>i)
arr1[i] = arr[i];

else
arr2[(arr.length-i)-1] = arr[i];


//First half array
System.out.println("First half array");
for(int i=0;i<arr.length/2;i++)
System.out.print(" " + arr1[i]);

//Second half array
System.out.println();
System.out.println("Second half array");
for(int i=arr.length/2-1;i>=0;i--)
System.out.print(" " + arr2[i]);









java array





share







New contributor




Ved Prakash is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.










share







New contributor




Ved Prakash is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








share



share






New contributor




Ved Prakash is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 9 mins ago









Ved PrakashVed Prakash

1013




1013




New contributor




Ved Prakash is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Ved Prakash is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Ved Prakash is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











  • $begingroup$
    Please explain this arr2[(arr.length-i)-1] = arr[i];
    $endgroup$
    – Mukul Kumar
    1 min ago
















  • $begingroup$
    Please explain this arr2[(arr.length-i)-1] = arr[i];
    $endgroup$
    – Mukul Kumar
    1 min ago















$begingroup$
Please explain this arr2[(arr.length-i)-1] = arr[i];
$endgroup$
– Mukul Kumar
1 min ago




$begingroup$
Please explain this arr2[(arr.length-i)-1] = arr[i];
$endgroup$
– Mukul Kumar
1 min ago










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