Set.add fails in a 3Sum3sum leetcode problem using 2sum3-Sum Problem in PythonMaximum sub array sum equal to kGiven a sorted array nums, remove the duplicates in-placeFind all combinations of 4 elements whose sum equals a target in PythonLeetcode Two Sum code in PythonLeetcode Three Sum in PythonHash table solution to twoSumA binary search solution to 3SumQuadratic solution to 3Sum

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Set.add fails in a 3Sum


3sum leetcode problem using 2sum3-Sum Problem in PythonMaximum sub array sum equal to kGiven a sorted array nums, remove the duplicates in-placeFind all combinations of 4 elements whose sum equals a target in PythonLeetcode Two Sum code in PythonLeetcode Three Sum in PythonHash table solution to twoSumA binary search solution to 3SumQuadratic solution to 3Sum













0












$begingroup$


I tried to solve the 3Sum problem in leetcodes




Given an array nums of n integers, are there elements a, b, c in nums such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero.



Note:



The solution set must not contain duplicate triplets.



Example:



Given array nums = [-1, 0, 1, 2, -1, -4],

A solution set is:
[
[-1, 0, 1],
[-1, -1, 2]
]



and my running codes



class Solution:
def threeSum(self, nums, target: int=0) -> List[List[int]]:
"""
:type nums: List[int]
:type target: int
"""
if len(nums) < 3: return []

lookup = nums[i]:i for i in range(len(nums)-1, -1, -1) #overwrite from the high
triplets = []
triplets_set = set()

for i in range(len(nums)):
num_1 = nums[i]
sub_target = target - num_1
# logging.debug(f"level_1_lookup: lookup")

for j in range(i+1, len(nums)):
num_2 = nums[j]
_j = lookup[num_2]
_i = lookup[num_1]
_k = j + 1

num_3 = sub_target - num_2
k = lookup.get(num_3) #

if k not in None, i, j: #don't reproduce itself
if num_1 == num_2 == num_3 == 0:
t = (0, 0, 0)
triplets_set.add(t)
#logging.debug(f"i i:_i, j j:_j, k k: _k")

if i != _i and j != _j and k != _k: continue #remove the identical copies

result = [num_1, num_2, num_3]
result.sort()
result = tuple(result)
triplets_set.add(result)

# logging.debug(f"j: j, _j: _j, k: k")
# logging.debug(f"lookup: lookup sub_nums: nums[j:] nresult: result")
# logging.info(f"ttriplets: tripletsnnnn")

triplets = [list(t) for t in triplets_set]
return triplets


As for the ports



 if k not in None, i, j: #don't reproduce itself 
if num_1 == num_2 == num_3 == 0:
t = (0, 0, 0)
triplets_set.add(t)


it produce a last result



[0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,00,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]


I cannot figure out what's the problem with my usage of tuple and set?









share







New contributor




Alice is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$
















    0












    $begingroup$


    I tried to solve the 3Sum problem in leetcodes




    Given an array nums of n integers, are there elements a, b, c in nums such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero.



    Note:



    The solution set must not contain duplicate triplets.



    Example:



    Given array nums = [-1, 0, 1, 2, -1, -4],

    A solution set is:
    [
    [-1, 0, 1],
    [-1, -1, 2]
    ]



    and my running codes



    class Solution:
    def threeSum(self, nums, target: int=0) -> List[List[int]]:
    """
    :type nums: List[int]
    :type target: int
    """
    if len(nums) < 3: return []

    lookup = nums[i]:i for i in range(len(nums)-1, -1, -1) #overwrite from the high
    triplets = []
    triplets_set = set()

    for i in range(len(nums)):
    num_1 = nums[i]
    sub_target = target - num_1
    # logging.debug(f"level_1_lookup: lookup")

    for j in range(i+1, len(nums)):
    num_2 = nums[j]
    _j = lookup[num_2]
    _i = lookup[num_1]
    _k = j + 1

    num_3 = sub_target - num_2
    k = lookup.get(num_3) #

    if k not in None, i, j: #don't reproduce itself
    if num_1 == num_2 == num_3 == 0:
    t = (0, 0, 0)
    triplets_set.add(t)
    #logging.debug(f"i i:_i, j j:_j, k k: _k")

    if i != _i and j != _j and k != _k: continue #remove the identical copies

    result = [num_1, num_2, num_3]
    result.sort()
    result = tuple(result)
    triplets_set.add(result)

    # logging.debug(f"j: j, _j: _j, k: k")
    # logging.debug(f"lookup: lookup sub_nums: nums[j:] nresult: result")
    # logging.info(f"ttriplets: tripletsnnnn")

    triplets = [list(t) for t in triplets_set]
    return triplets


    As for the ports



     if k not in None, i, j: #don't reproduce itself 
    if num_1 == num_2 == num_3 == 0:
    t = (0, 0, 0)
    triplets_set.add(t)


    it produce a last result



    [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,00,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]


    I cannot figure out what's the problem with my usage of tuple and set?









    share







    New contributor




    Alice is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$














      0












      0








      0





      $begingroup$


      I tried to solve the 3Sum problem in leetcodes




      Given an array nums of n integers, are there elements a, b, c in nums such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero.



      Note:



      The solution set must not contain duplicate triplets.



      Example:



      Given array nums = [-1, 0, 1, 2, -1, -4],

      A solution set is:
      [
      [-1, 0, 1],
      [-1, -1, 2]
      ]



      and my running codes



      class Solution:
      def threeSum(self, nums, target: int=0) -> List[List[int]]:
      """
      :type nums: List[int]
      :type target: int
      """
      if len(nums) < 3: return []

      lookup = nums[i]:i for i in range(len(nums)-1, -1, -1) #overwrite from the high
      triplets = []
      triplets_set = set()

      for i in range(len(nums)):
      num_1 = nums[i]
      sub_target = target - num_1
      # logging.debug(f"level_1_lookup: lookup")

      for j in range(i+1, len(nums)):
      num_2 = nums[j]
      _j = lookup[num_2]
      _i = lookup[num_1]
      _k = j + 1

      num_3 = sub_target - num_2
      k = lookup.get(num_3) #

      if k not in None, i, j: #don't reproduce itself
      if num_1 == num_2 == num_3 == 0:
      t = (0, 0, 0)
      triplets_set.add(t)
      #logging.debug(f"i i:_i, j j:_j, k k: _k")

      if i != _i and j != _j and k != _k: continue #remove the identical copies

      result = [num_1, num_2, num_3]
      result.sort()
      result = tuple(result)
      triplets_set.add(result)

      # logging.debug(f"j: j, _j: _j, k: k")
      # logging.debug(f"lookup: lookup sub_nums: nums[j:] nresult: result")
      # logging.info(f"ttriplets: tripletsnnnn")

      triplets = [list(t) for t in triplets_set]
      return triplets


      As for the ports



       if k not in None, i, j: #don't reproduce itself 
      if num_1 == num_2 == num_3 == 0:
      t = (0, 0, 0)
      triplets_set.add(t)


      it produce a last result



      [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,00,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]


      I cannot figure out what's the problem with my usage of tuple and set?









      share







      New contributor




      Alice is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      I tried to solve the 3Sum problem in leetcodes




      Given an array nums of n integers, are there elements a, b, c in nums such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero.



      Note:



      The solution set must not contain duplicate triplets.



      Example:



      Given array nums = [-1, 0, 1, 2, -1, -4],

      A solution set is:
      [
      [-1, 0, 1],
      [-1, -1, 2]
      ]



      and my running codes



      class Solution:
      def threeSum(self, nums, target: int=0) -> List[List[int]]:
      """
      :type nums: List[int]
      :type target: int
      """
      if len(nums) < 3: return []

      lookup = nums[i]:i for i in range(len(nums)-1, -1, -1) #overwrite from the high
      triplets = []
      triplets_set = set()

      for i in range(len(nums)):
      num_1 = nums[i]
      sub_target = target - num_1
      # logging.debug(f"level_1_lookup: lookup")

      for j in range(i+1, len(nums)):
      num_2 = nums[j]
      _j = lookup[num_2]
      _i = lookup[num_1]
      _k = j + 1

      num_3 = sub_target - num_2
      k = lookup.get(num_3) #

      if k not in None, i, j: #don't reproduce itself
      if num_1 == num_2 == num_3 == 0:
      t = (0, 0, 0)
      triplets_set.add(t)
      #logging.debug(f"i i:_i, j j:_j, k k: _k")

      if i != _i and j != _j and k != _k: continue #remove the identical copies

      result = [num_1, num_2, num_3]
      result.sort()
      result = tuple(result)
      triplets_set.add(result)

      # logging.debug(f"j: j, _j: _j, k: k")
      # logging.debug(f"lookup: lookup sub_nums: nums[j:] nresult: result")
      # logging.info(f"ttriplets: tripletsnnnn")

      triplets = [list(t) for t in triplets_set]
      return triplets


      As for the ports



       if k not in None, i, j: #don't reproduce itself 
      if num_1 == num_2 == num_3 == 0:
      t = (0, 0, 0)
      triplets_set.add(t)


      it produce a last result



      [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,00,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]


      I cannot figure out what's the problem with my usage of tuple and set?







      python





      share







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      Alice is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.










      share







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      Check out our Code of Conduct.








      share



      share






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      asked 3 mins ago









      AliceAlice

      1774




      1774




      New contributor




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      Alice is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






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