Set.add fails in a 3Sum3sum leetcode problem using 2sum3-Sum Problem in PythonMaximum sub array sum equal to kGiven a sorted array nums, remove the duplicates in-placeFind all combinations of 4 elements whose sum equals a target in PythonLeetcode Two Sum code in PythonLeetcode Three Sum in PythonHash table solution to twoSumA binary search solution to 3SumQuadratic solution to 3Sum
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Set.add fails in a 3Sum
3sum leetcode problem using 2sum3-Sum Problem in PythonMaximum sub array sum equal to kGiven a sorted array nums, remove the duplicates in-placeFind all combinations of 4 elements whose sum equals a target in PythonLeetcode Two Sum code in PythonLeetcode Three Sum in PythonHash table solution to twoSumA binary search solution to 3SumQuadratic solution to 3Sum
$begingroup$
I tried to solve the 3Sum problem in leetcodes
Given an array
nums
of n integers, are there elements a, b, c innums
such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero.
Note:
The solution set must not contain duplicate triplets.
Example:
Given array nums = [-1, 0, 1, 2, -1, -4],
A solution set is:
[
[-1, 0, 1],
[-1, -1, 2]
]
and my running codes
class Solution:
def threeSum(self, nums, target: int=0) -> List[List[int]]:
"""
:type nums: List[int]
:type target: int
"""
if len(nums) < 3: return []
lookup = nums[i]:i for i in range(len(nums)-1, -1, -1) #overwrite from the high
triplets = []
triplets_set = set()
for i in range(len(nums)):
num_1 = nums[i]
sub_target = target - num_1
# logging.debug(f"level_1_lookup: lookup")
for j in range(i+1, len(nums)):
num_2 = nums[j]
_j = lookup[num_2]
_i = lookup[num_1]
_k = j + 1
num_3 = sub_target - num_2
k = lookup.get(num_3) #
if k not in None, i, j: #don't reproduce itself
if num_1 == num_2 == num_3 == 0:
t = (0, 0, 0)
triplets_set.add(t)
#logging.debug(f"i i:_i, j j:_j, k k: _k")
if i != _i and j != _j and k != _k: continue #remove the identical copies
result = [num_1, num_2, num_3]
result.sort()
result = tuple(result)
triplets_set.add(result)
# logging.debug(f"j: j, _j: _j, k: k")
# logging.debug(f"lookup: lookup sub_nums: nums[j:] nresult: result")
# logging.info(f"ttriplets: tripletsnnnn")
triplets = [list(t) for t in triplets_set]
return triplets
As for the ports
if k not in None, i, j: #don't reproduce itself
if num_1 == num_2 == num_3 == 0:
t = (0, 0, 0)
triplets_set.add(t)
it produce a last result
[0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,00,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]
I cannot figure out what's the problem with my usage of tuple and set?
python
New contributor
$endgroup$
add a comment |
$begingroup$
I tried to solve the 3Sum problem in leetcodes
Given an array
nums
of n integers, are there elements a, b, c innums
such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero.
Note:
The solution set must not contain duplicate triplets.
Example:
Given array nums = [-1, 0, 1, 2, -1, -4],
A solution set is:
[
[-1, 0, 1],
[-1, -1, 2]
]
and my running codes
class Solution:
def threeSum(self, nums, target: int=0) -> List[List[int]]:
"""
:type nums: List[int]
:type target: int
"""
if len(nums) < 3: return []
lookup = nums[i]:i for i in range(len(nums)-1, -1, -1) #overwrite from the high
triplets = []
triplets_set = set()
for i in range(len(nums)):
num_1 = nums[i]
sub_target = target - num_1
# logging.debug(f"level_1_lookup: lookup")
for j in range(i+1, len(nums)):
num_2 = nums[j]
_j = lookup[num_2]
_i = lookup[num_1]
_k = j + 1
num_3 = sub_target - num_2
k = lookup.get(num_3) #
if k not in None, i, j: #don't reproduce itself
if num_1 == num_2 == num_3 == 0:
t = (0, 0, 0)
triplets_set.add(t)
#logging.debug(f"i i:_i, j j:_j, k k: _k")
if i != _i and j != _j and k != _k: continue #remove the identical copies
result = [num_1, num_2, num_3]
result.sort()
result = tuple(result)
triplets_set.add(result)
# logging.debug(f"j: j, _j: _j, k: k")
# logging.debug(f"lookup: lookup sub_nums: nums[j:] nresult: result")
# logging.info(f"ttriplets: tripletsnnnn")
triplets = [list(t) for t in triplets_set]
return triplets
As for the ports
if k not in None, i, j: #don't reproduce itself
if num_1 == num_2 == num_3 == 0:
t = (0, 0, 0)
triplets_set.add(t)
it produce a last result
[0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,00,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]
I cannot figure out what's the problem with my usage of tuple and set?
python
New contributor
$endgroup$
add a comment |
$begingroup$
I tried to solve the 3Sum problem in leetcodes
Given an array
nums
of n integers, are there elements a, b, c innums
such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero.
Note:
The solution set must not contain duplicate triplets.
Example:
Given array nums = [-1, 0, 1, 2, -1, -4],
A solution set is:
[
[-1, 0, 1],
[-1, -1, 2]
]
and my running codes
class Solution:
def threeSum(self, nums, target: int=0) -> List[List[int]]:
"""
:type nums: List[int]
:type target: int
"""
if len(nums) < 3: return []
lookup = nums[i]:i for i in range(len(nums)-1, -1, -1) #overwrite from the high
triplets = []
triplets_set = set()
for i in range(len(nums)):
num_1 = nums[i]
sub_target = target - num_1
# logging.debug(f"level_1_lookup: lookup")
for j in range(i+1, len(nums)):
num_2 = nums[j]
_j = lookup[num_2]
_i = lookup[num_1]
_k = j + 1
num_3 = sub_target - num_2
k = lookup.get(num_3) #
if k not in None, i, j: #don't reproduce itself
if num_1 == num_2 == num_3 == 0:
t = (0, 0, 0)
triplets_set.add(t)
#logging.debug(f"i i:_i, j j:_j, k k: _k")
if i != _i and j != _j and k != _k: continue #remove the identical copies
result = [num_1, num_2, num_3]
result.sort()
result = tuple(result)
triplets_set.add(result)
# logging.debug(f"j: j, _j: _j, k: k")
# logging.debug(f"lookup: lookup sub_nums: nums[j:] nresult: result")
# logging.info(f"ttriplets: tripletsnnnn")
triplets = [list(t) for t in triplets_set]
return triplets
As for the ports
if k not in None, i, j: #don't reproduce itself
if num_1 == num_2 == num_3 == 0:
t = (0, 0, 0)
triplets_set.add(t)
it produce a last result
[0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,00,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]
I cannot figure out what's the problem with my usage of tuple and set?
python
New contributor
$endgroup$
I tried to solve the 3Sum problem in leetcodes
Given an array
nums
of n integers, are there elements a, b, c innums
such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero.
Note:
The solution set must not contain duplicate triplets.
Example:
Given array nums = [-1, 0, 1, 2, -1, -4],
A solution set is:
[
[-1, 0, 1],
[-1, -1, 2]
]
and my running codes
class Solution:
def threeSum(self, nums, target: int=0) -> List[List[int]]:
"""
:type nums: List[int]
:type target: int
"""
if len(nums) < 3: return []
lookup = nums[i]:i for i in range(len(nums)-1, -1, -1) #overwrite from the high
triplets = []
triplets_set = set()
for i in range(len(nums)):
num_1 = nums[i]
sub_target = target - num_1
# logging.debug(f"level_1_lookup: lookup")
for j in range(i+1, len(nums)):
num_2 = nums[j]
_j = lookup[num_2]
_i = lookup[num_1]
_k = j + 1
num_3 = sub_target - num_2
k = lookup.get(num_3) #
if k not in None, i, j: #don't reproduce itself
if num_1 == num_2 == num_3 == 0:
t = (0, 0, 0)
triplets_set.add(t)
#logging.debug(f"i i:_i, j j:_j, k k: _k")
if i != _i and j != _j and k != _k: continue #remove the identical copies
result = [num_1, num_2, num_3]
result.sort()
result = tuple(result)
triplets_set.add(result)
# logging.debug(f"j: j, _j: _j, k: k")
# logging.debug(f"lookup: lookup sub_nums: nums[j:] nresult: result")
# logging.info(f"ttriplets: tripletsnnnn")
triplets = [list(t) for t in triplets_set]
return triplets
As for the ports
if k not in None, i, j: #don't reproduce itself
if num_1 == num_2 == num_3 == 0:
t = (0, 0, 0)
triplets_set.add(t)
it produce a last result
[0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,00,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]
I cannot figure out what's the problem with my usage of tuple and set?
python
python
New contributor
New contributor
New contributor
asked 3 mins ago
AliceAlice
1774
1774
New contributor
New contributor
add a comment |
add a comment |
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