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Hacking a Safe Lock after 3 tries


Faulty Combination LockCrack the (Poorly Designed) SafeLock OptimisationCracking a combination lockWhose lock is lock-ier?Cristiano Ronaldo's soccer puzzleKey and lock puzzle8-bit Lock and KeyHacking an electronic keypadcrack this code #1965













10












$begingroup$


My friend has a safe lock, with a numeric password of 4 digits (varying between 0-9 each). She lost the password and looked for my help. Fortunately, I was able to hack it. I could try some different combinations and check how many numbers I got right.



I tried the number 8086 => Only 1 number is right, but in the wrong position.



I tried the number 8857 => Only 1 number is right, but in the wrong position.



I tried the number 0159 => You got 3 numbers right, all in the correct position.



And then the hack stopped working. If I insert just one wrong number, the safe lock will break.



Am I able to open this lock with the information provided by my hack? If so, what is the password?










share|improve this question









$endgroup$
















    10












    $begingroup$


    My friend has a safe lock, with a numeric password of 4 digits (varying between 0-9 each). She lost the password and looked for my help. Fortunately, I was able to hack it. I could try some different combinations and check how many numbers I got right.



    I tried the number 8086 => Only 1 number is right, but in the wrong position.



    I tried the number 8857 => Only 1 number is right, but in the wrong position.



    I tried the number 0159 => You got 3 numbers right, all in the correct position.



    And then the hack stopped working. If I insert just one wrong number, the safe lock will break.



    Am I able to open this lock with the information provided by my hack? If so, what is the password?










    share|improve this question









    $endgroup$














      10












      10








      10





      $begingroup$


      My friend has a safe lock, with a numeric password of 4 digits (varying between 0-9 each). She lost the password and looked for my help. Fortunately, I was able to hack it. I could try some different combinations and check how many numbers I got right.



      I tried the number 8086 => Only 1 number is right, but in the wrong position.



      I tried the number 8857 => Only 1 number is right, but in the wrong position.



      I tried the number 0159 => You got 3 numbers right, all in the correct position.



      And then the hack stopped working. If I insert just one wrong number, the safe lock will break.



      Am I able to open this lock with the information provided by my hack? If so, what is the password?










      share|improve this question









      $endgroup$




      My friend has a safe lock, with a numeric password of 4 digits (varying between 0-9 each). She lost the password and looked for my help. Fortunately, I was able to hack it. I could try some different combinations and check how many numbers I got right.



      I tried the number 8086 => Only 1 number is right, but in the wrong position.



      I tried the number 8857 => Only 1 number is right, but in the wrong position.



      I tried the number 0159 => You got 3 numbers right, all in the correct position.



      And then the hack stopped working. If I insert just one wrong number, the safe lock will break.



      Am I able to open this lock with the information provided by my hack? If so, what is the password?







      combinatorics mastermind






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 8 hours ago









      ChaoticChaotic

      537214




      537214




















          1 Answer
          1






          active

          oldest

          votes


















          11












          $begingroup$

          I think the correct password is




          0179




          Reasoning




          Combining the second and third clues tells us that '5' is not in the combination, otherwise it would be in the correct position in the second combination. Therefore, 0, 1, and 9 are all in the correct position in the last combination. The first clue tells us that the third digit is not 8. Using the second clue again, the only remaining option is 7.







          share|improve this answer









          $endgroup$












          • $begingroup$
            Ah, sniped! Well done!
            $endgroup$
            – Matt
            8 hours ago










          • $begingroup$
            Seconds away from beating you!
            $endgroup$
            – Greg
            8 hours ago










          • $begingroup$
            Well done!! Got me too!
            $endgroup$
            – El-Guest
            8 hours ago










          Your Answer





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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          11












          $begingroup$

          I think the correct password is




          0179




          Reasoning




          Combining the second and third clues tells us that '5' is not in the combination, otherwise it would be in the correct position in the second combination. Therefore, 0, 1, and 9 are all in the correct position in the last combination. The first clue tells us that the third digit is not 8. Using the second clue again, the only remaining option is 7.







          share|improve this answer









          $endgroup$












          • $begingroup$
            Ah, sniped! Well done!
            $endgroup$
            – Matt
            8 hours ago










          • $begingroup$
            Seconds away from beating you!
            $endgroup$
            – Greg
            8 hours ago










          • $begingroup$
            Well done!! Got me too!
            $endgroup$
            – El-Guest
            8 hours ago















          11












          $begingroup$

          I think the correct password is




          0179




          Reasoning




          Combining the second and third clues tells us that '5' is not in the combination, otherwise it would be in the correct position in the second combination. Therefore, 0, 1, and 9 are all in the correct position in the last combination. The first clue tells us that the third digit is not 8. Using the second clue again, the only remaining option is 7.







          share|improve this answer









          $endgroup$












          • $begingroup$
            Ah, sniped! Well done!
            $endgroup$
            – Matt
            8 hours ago










          • $begingroup$
            Seconds away from beating you!
            $endgroup$
            – Greg
            8 hours ago










          • $begingroup$
            Well done!! Got me too!
            $endgroup$
            – El-Guest
            8 hours ago













          11












          11








          11





          $begingroup$

          I think the correct password is




          0179




          Reasoning




          Combining the second and third clues tells us that '5' is not in the combination, otherwise it would be in the correct position in the second combination. Therefore, 0, 1, and 9 are all in the correct position in the last combination. The first clue tells us that the third digit is not 8. Using the second clue again, the only remaining option is 7.







          share|improve this answer









          $endgroup$



          I think the correct password is




          0179




          Reasoning




          Combining the second and third clues tells us that '5' is not in the combination, otherwise it would be in the correct position in the second combination. Therefore, 0, 1, and 9 are all in the correct position in the last combination. The first clue tells us that the third digit is not 8. Using the second clue again, the only remaining option is 7.








          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 8 hours ago









          hexominohexomino

          43.3k3129207




          43.3k3129207











          • $begingroup$
            Ah, sniped! Well done!
            $endgroup$
            – Matt
            8 hours ago










          • $begingroup$
            Seconds away from beating you!
            $endgroup$
            – Greg
            8 hours ago










          • $begingroup$
            Well done!! Got me too!
            $endgroup$
            – El-Guest
            8 hours ago
















          • $begingroup$
            Ah, sniped! Well done!
            $endgroup$
            – Matt
            8 hours ago










          • $begingroup$
            Seconds away from beating you!
            $endgroup$
            – Greg
            8 hours ago










          • $begingroup$
            Well done!! Got me too!
            $endgroup$
            – El-Guest
            8 hours ago















          $begingroup$
          Ah, sniped! Well done!
          $endgroup$
          – Matt
          8 hours ago




          $begingroup$
          Ah, sniped! Well done!
          $endgroup$
          – Matt
          8 hours ago












          $begingroup$
          Seconds away from beating you!
          $endgroup$
          – Greg
          8 hours ago




          $begingroup$
          Seconds away from beating you!
          $endgroup$
          – Greg
          8 hours ago












          $begingroup$
          Well done!! Got me too!
          $endgroup$
          – El-Guest
          8 hours ago




          $begingroup$
          Well done!! Got me too!
          $endgroup$
          – El-Guest
          8 hours ago

















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