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0

$begingroup$

I have a list of strings. I need to list them in rows and columns. Each row should not have more than "cols" number of values. Each of the values in a given row should be "step" away from the previous value. The values should appear only once in the output. Here is what I have. Any better way to write this code? Thanks a bunch.
e.g.:

cols = 4
step = 10
vlist = ["Value" + str(i+1) for i in range(100)]

vlen = len(vlist)
start = 0
while start < vlen and start < step:
 num = 0
 for idx in range(start, vlen, step):
 if num < cols:
 print(vlist[idx], end=", ")
 num += 1
 print("n")
 start += 1

python python-3.x

share|improve this question

asked 39 mins ago

RebornCodeLoverRebornCodeLover

1

New contributor

RebornCodeLover is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Welcome to Code Review! Is Each [value] should be "step" away from the previous value an "external" requirement? ((Block-) Quote the specification of the result to achieve.) Another interpretation is In a monospace font, each value shall be output 10 places to the right of the preceding one, the advantage being all values getting displayed.
  $endgroup$
  – greybeard
  14 mins ago
  

  
  
  
  

add a comment | 

0

$begingroup$

I have a list of strings. I need to list them in rows and columns. Each row should not have more than "cols" number of values. Each of the values in a given row should be "step" away from the previous value. The values should appear only once in the output. Here is what I have. Any better way to write this code? Thanks a bunch.
e.g.:

cols = 4
step = 10
vlist = ["Value" + str(i+1) for i in range(100)]

vlen = len(vlist)
start = 0
while start < vlen and start < step:
 num = 0
 for idx in range(start, vlen, step):
 if num < cols:
 print(vlist[idx], end=", ")
 num += 1
 print("n")
 start += 1

python python-3.x

share|improve this question

asked 39 mins ago

RebornCodeLoverRebornCodeLover

1

New contributor

RebornCodeLover is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Welcome to Code Review! Is Each [value] should be "step" away from the previous value an "external" requirement? ((Block-) Quote the specification of the result to achieve.) Another interpretation is In a monospace font, each value shall be output 10 places to the right of the preceding one, the advantage being all values getting displayed.
  $endgroup$
  – greybeard
  14 mins ago
  

  
  
  
  

add a comment | 

$begingroup$

I have a list of strings. I need to list them in rows and columns. Each row should not have more than "cols" number of values. Each of the values in a given row should be "step" away from the previous value. The values should appear only once in the output. Here is what I have. Any better way to write this code? Thanks a bunch.
e.g.:

cols = 4
step = 10
vlist = ["Value" + str(i+1) for i in range(100)]

vlen = len(vlist)
start = 0
while start < vlen and start < step:
 num = 0
 for idx in range(start, vlen, step):
 if num < cols:
 print(vlist[idx], end=", ")
 num += 1
 print("n")
 start += 1

python python-3.x

share|improve this question

asked 39 mins ago

RebornCodeLoverRebornCodeLover

1

New contributor

RebornCodeLover is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

cols = 4
step = 10
vlist = ["Value" + str(i+1) for i in range(100)]

vlen = len(vlist)
start = 0
while start < vlen and start < step:
 num = 0
 for idx in range(start, vlen, step):
 if num < cols:
 print(vlist[idx], end=", ")
 num += 1
 print("n")
 start += 1

share|improve this question

asked 39 mins ago

RebornCodeLoverRebornCodeLover

1

New contributor

RebornCodeLover is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

asked 39 mins ago

RebornCodeLoverRebornCodeLover

1

New contributor

RebornCodeLover is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 39 mins ago

RebornCodeLoverRebornCodeLover

1

New contributor

RebornCodeLover is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 39 mins ago

RebornCodeLoverRebornCodeLover

1