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Mutable Linked List in Scala

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0

$begingroup$

Scala newbie here. I'm trying to implement a mutable linked list in Scala. So far, I am only supporting the add() operation. Here's my stab at it:

class MutableList[T] 

 class Node[T](val value: T) 
 var next: Node[T] = null
 def hasNext = (next != null)
 

 var first, last: Node[T] = null
 var size = 0

 def add(value: T) = 
 val newNode = new Node[T](value)
 if (first == null) 
 assert(size == 0)
 first = newNode
 last = newNode
 else 
 last.next = newNode
 
 size += 1
 

 override def toString = 
 def getValues() = 
 var current = first
 for (i <- 1 to size) yield 
 val valStr = current.value.toString
 current = current.next
 valStr
 
 
 getValues().mkString(",")
 

I know that a mutable data structure is not the best thing to use/implement in Scala. But I'm just experimenting and was wondering if there is a more functional Scala way of writing this?

scala

share

asked 1 hour ago

Aashish DattaniAashish Dattani

1

New contributor

Aashish Dattani is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

add a comment | 

0

$begingroup$

Scala newbie here. I'm trying to implement a mutable linked list in Scala. So far, I am only supporting the add() operation. Here's my stab at it:

class MutableList[T] 

 class Node[T](val value: T) 
 var next: Node[T] = null
 def hasNext = (next != null)
 

 var first, last: Node[T] = null
 var size = 0

 def add(value: T) = 
 val newNode = new Node[T](value)
 if (first == null) 
 assert(size == 0)
 first = newNode
 last = newNode
 else 
 last.next = newNode
 
 size += 1
 

 override def toString = 
 def getValues() = 
 var current = first
 for (i <- 1 to size) yield 
 val valStr = current.value.toString
 current = current.next
 valStr
 
 
 getValues().mkString(",")
 

I know that a mutable data structure is not the best thing to use/implement in Scala. But I'm just experimenting and was wondering if there is a more functional Scala way of writing this?

scala

share

asked 1 hour ago

Aashish DattaniAashish Dattani

1

New contributor

Aashish Dattani is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

add a comment | 

$begingroup$

Scala newbie here. I'm trying to implement a mutable linked list in Scala. So far, I am only supporting the add() operation. Here's my stab at it:

class MutableList[T] 

 class Node[T](val value: T) 
 var next: Node[T] = null
 def hasNext = (next != null)
 

 var first, last: Node[T] = null
 var size = 0

 def add(value: T) = 
 val newNode = new Node[T](value)
 if (first == null) 
 assert(size == 0)
 first = newNode
 last = newNode
 else 
 last.next = newNode
 
 size += 1
 

 override def toString = 
 def getValues() = 
 var current = first
 for (i <- 1 to size) yield 
 val valStr = current.value.toString
 current = current.next
 valStr
 
 
 getValues().mkString(",")
 

I know that a mutable data structure is not the best thing to use/implement in Scala. But I'm just experimenting and was wondering if there is a more functional Scala way of writing this?

scala

share

asked 1 hour ago

Aashish DattaniAashish Dattani

1

New contributor

Aashish Dattani is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

class MutableList[T] 

 class Node[T](val value: T) 
 var next: Node[T] = null
 def hasNext = (next != null)
 

 var first, last: Node[T] = null
 var size = 0

 def add(value: T) = 
 val newNode = new Node[T](value)
 if (first == null) 
 assert(size == 0)
 first = newNode
 last = newNode
 else 
 last.next = newNode
 
 size += 1
 

 override def toString = 
 def getValues() = 
 var current = first
 for (i <- 1 to size) yield 
 val valStr = current.value.toString
 current = current.next
 valStr
 
 
 getValues().mkString(",")
 

share

asked 1 hour ago

Aashish DattaniAashish Dattani

1

New contributor

Aashish Dattani is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share

asked 1 hour ago

Aashish DattaniAashish Dattani

1

New contributor

Aashish Dattani is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 1 hour ago

Aashish DattaniAashish Dattani

1

New contributor

Aashish Dattani is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 1 hour ago

Aashish DattaniAashish Dattani

1