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Examples of smooth manifolds admitting inbetween one and a continuum of complex structures
Smooth and analytic structures on low dimensional euclidian spacesExistence of closed manifolds with more than 3 linearly independent complex structures?Non-Integrable Almost-Complex Structures for Homogeneous SpacesAlmost Complex Structure approach to Deformation of Compact Complex ManifoldsDoes every smoothly embedded surface $mathbbR^3$ inherit a natural complex structure, and if so, which one?Obstructions to deformations of complex manifoldsClassification of complex structures on $mathbbR^2n$Spin^c structures on manifolds with almost complex structureOpen subsets of Euclidean space in dimension 5 and higher admitting exotic smooth structuresDo smooth manifolds admit unique cubical structures?
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For smooth manifolds it is known that they can admit a unique, finitely many, or a continuum of distinct smooth structures (I don't know whether there are any examples admitting precisely a countably infinite number).
For complex manifolds there are examples of smooth manifolds admitting a unique complex structure ($mathbbCP^1$) or a continuum (compact Riemann surfaces, K3 surfaces, etc.) but are there examples admitting only finitely many or a countably infinite number?
By deformation theory the tangent space to the moduli space of complex structures on $X$ should be given by $H^1(X, TX)$ (at least morally) so it must be necessary for this to vanish for every possible complex structure on $X$ to have any hope.
dg.differential-geometry complex-geometry differential-topology
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For smooth manifolds it is known that they can admit a unique, finitely many, or a continuum of distinct smooth structures (I don't know whether there are any examples admitting precisely a countably infinite number).
For complex manifolds there are examples of smooth manifolds admitting a unique complex structure ($mathbbCP^1$) or a continuum (compact Riemann surfaces, K3 surfaces, etc.) but are there examples admitting only finitely many or a countably infinite number?
By deformation theory the tangent space to the moduli space of complex structures on $X$ should be given by $H^1(X, TX)$ (at least morally) so it must be necessary for this to vanish for every possible complex structure on $X$ to have any hope.
dg.differential-geometry complex-geometry differential-topology
New contributor
John McCarthy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
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For smooth manifolds it is known that they can admit a unique, finitely many, or a continuum of distinct smooth structures (I don't know whether there are any examples admitting precisely a countably infinite number).
For complex manifolds there are examples of smooth manifolds admitting a unique complex structure ($mathbbCP^1$) or a continuum (compact Riemann surfaces, K3 surfaces, etc.) but are there examples admitting only finitely many or a countably infinite number?
By deformation theory the tangent space to the moduli space of complex structures on $X$ should be given by $H^1(X, TX)$ (at least morally) so it must be necessary for this to vanish for every possible complex structure on $X$ to have any hope.
dg.differential-geometry complex-geometry differential-topology
New contributor
John McCarthy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
For smooth manifolds it is known that they can admit a unique, finitely many, or a continuum of distinct smooth structures (I don't know whether there are any examples admitting precisely a countably infinite number).
For complex manifolds there are examples of smooth manifolds admitting a unique complex structure ($mathbbCP^1$) or a continuum (compact Riemann surfaces, K3 surfaces, etc.) but are there examples admitting only finitely many or a countably infinite number?
By deformation theory the tangent space to the moduli space of complex structures on $X$ should be given by $H^1(X, TX)$ (at least morally) so it must be necessary for this to vanish for every possible complex structure on $X$ to have any hope.
dg.differential-geometry complex-geometry differential-topology
dg.differential-geometry complex-geometry differential-topology
New contributor
John McCarthy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
John McCarthy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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asked 3 hours ago
John McCarthyJohn McCarthy
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Examples of smooth manifolds admitting finitely many complex structures are provided by some holomorphically rigid complex varieties.
For instance, considering fake projective planes (i.e., smooth compact complex surfaces which are not the complex projective plane but have the same Betti numbers as the
complex projective plane), there are $100$ examples determined up to biholomorphism, but only $50$ examples determined up to isometry.
In fact, the $4$-manifold underlying any fake projective plane admits precisely two inequivalent complex structures, that are exchanged by complex conjugation.
Moreover, by standard results on rigidity, any Kähler surface with the same fundamental group as a fake projective plane is actually biholomorphic or conjugate biholomorphic to it.
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Examples of smooth manifolds admitting finitely many complex structures are provided by some holomorphically rigid complex varieties.
For instance, considering fake projective planes (i.e., smooth compact complex surfaces which are not the complex projective plane but have the same Betti numbers as the
complex projective plane), there are $100$ examples determined up to biholomorphism, but only $50$ examples determined up to isometry.
In fact, the $4$-manifold underlying any fake projective plane admits precisely two inequivalent complex structures, that are exchanged by complex conjugation.
Moreover, by standard results on rigidity, any Kähler surface with the same fundamental group as a fake projective plane is actually biholomorphic or conjugate biholomorphic to it.
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$begingroup$
Examples of smooth manifolds admitting finitely many complex structures are provided by some holomorphically rigid complex varieties.
For instance, considering fake projective planes (i.e., smooth compact complex surfaces which are not the complex projective plane but have the same Betti numbers as the
complex projective plane), there are $100$ examples determined up to biholomorphism, but only $50$ examples determined up to isometry.
In fact, the $4$-manifold underlying any fake projective plane admits precisely two inequivalent complex structures, that are exchanged by complex conjugation.
Moreover, by standard results on rigidity, any Kähler surface with the same fundamental group as a fake projective plane is actually biholomorphic or conjugate biholomorphic to it.
$endgroup$
add a comment |
$begingroup$
Examples of smooth manifolds admitting finitely many complex structures are provided by some holomorphically rigid complex varieties.
For instance, considering fake projective planes (i.e., smooth compact complex surfaces which are not the complex projective plane but have the same Betti numbers as the
complex projective plane), there are $100$ examples determined up to biholomorphism, but only $50$ examples determined up to isometry.
In fact, the $4$-manifold underlying any fake projective plane admits precisely two inequivalent complex structures, that are exchanged by complex conjugation.
Moreover, by standard results on rigidity, any Kähler surface with the same fundamental group as a fake projective plane is actually biholomorphic or conjugate biholomorphic to it.
$endgroup$
Examples of smooth manifolds admitting finitely many complex structures are provided by some holomorphically rigid complex varieties.
For instance, considering fake projective planes (i.e., smooth compact complex surfaces which are not the complex projective plane but have the same Betti numbers as the
complex projective plane), there are $100$ examples determined up to biholomorphism, but only $50$ examples determined up to isometry.
In fact, the $4$-manifold underlying any fake projective plane admits precisely two inequivalent complex structures, that are exchanged by complex conjugation.
Moreover, by standard results on rigidity, any Kähler surface with the same fundamental group as a fake projective plane is actually biholomorphic or conjugate biholomorphic to it.
edited 53 mins ago
answered 3 hours ago
Francesco PolizziFrancesco Polizzi
48.4k3129211
48.4k3129211
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