finding a key from values(which are list) in dict Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern) Announcing the arrival of Valued Associate #679: Cesar Manara Unicorn Meta Zoo #1: Why another podcast?LRU cache design using dict and doubly linked listGroup a list of `dict` by all keys except oneFinding line numbers of duplicate lines in a log fileMatching two lists of dicts, strictly and more looselyList all possible permutations from a python dictionary of listsList class object, which only contains lists as elementsCheck if elements of a list are incorporated in a nested dictSplit dictionary of lists into two dicts based on binary valuesTransforming a dict of lists into a list of dictsRemoving Dicts with Null values from Only the End of a List
Shimano 105 brifters (5800) and Avid BB5 compatibility
Can gravitational waves pass through a black hole?
Keep at all times, the minus sign above aligned with minus sign below
Is there night in Alpha Complex?
Did John Wesley plagiarize Matthew Henry...?
What helicopter has the most rotor blades?
How to get a flat-head nail out of a piece of wood?
Was the pager message from Nick Fury to Captain Marvel unnecessary?
How do I find my Spellcasting Ability for my D&D character?
By what mechanism was the 2017 UK General Election called?
How can I list files in reverse time order by a command and pass them as arguments to another command?
Flight departed from the gate 5 min before scheduled departure time. Refund options
IC on Digikey is 5x more expensive than board containing same IC on Alibaba: How?
Pointing to problems without suggesting solutions
Should man-made satellites feature an intelligent inverted "cow catcher"?
French equivalents of おしゃれは足元から (Every good outfit starts with the shoes)
The Nth Gryphon Number
Table formatting with tabularx?
What did Turing mean when saying that "machines cannot give rise to surprises" is due to a fallacy?
How do you cope with tons of web fonts when copying and pasting from web pages?
Why are two-digit numbers in Jonathan Swift's "Gulliver's Travels" (1726) written in "German style"?
How many time has Arya actually used Needle?
Improvising over quartal voicings
Can one Knight really make another one a Knight?
finding a key from values(which are list) in dict
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)
Announcing the arrival of Valued Associate #679: Cesar Manara
Unicorn Meta Zoo #1: Why another podcast?LRU cache design using dict and doubly linked listGroup a list of `dict` by all keys except oneFinding line numbers of duplicate lines in a log fileMatching two lists of dicts, strictly and more looselyList all possible permutations from a python dictionary of listsList class object, which only contains lists as elementsCheck if elements of a list are incorporated in a nested dictSplit dictionary of lists into two dicts based on binary valuesTransforming a dict of lists into a list of dictsRemoving Dicts with Null values from Only the End of a List
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
$begingroup$
I have a dict
x = 'a':[1,2,3], 'b':[4,5,6]
and I have to extract a key based on an input, in this case assume it is 3
So my output should be a
Here's my code:
x = 'a':[1,2,3], 'b':[4,5,6]
n = 3
output = [k for k,v in x.items() if n in v]
print(output[0])
Can it be done more efficiently?
Elements in the lists are uniques. eg. value 3 will only be in one list.
python python-3.x
asked 7 mins ago
AkshayNevrekarAkshayNevrekar
1205
$endgroup$
add a comment |
$begingroup$
I have a dict
x = 'a':[1,2,3], 'b':[4,5,6]
and I have to extract a key based on an input, in this case assume it is 3
So my output should be a
Here's my code:
x = 'a':[1,2,3], 'b':[4,5,6]
n = 3
output = [k for k,v in x.items() if n in v]
print(output[0])
Can it be done more efficiently?
Elements in the lists are uniques. eg. value 3 will only be in one list.
python python-3.x
asked 7 mins ago
AkshayNevrekarAkshayNevrekar
1205
$endgroup$
add a comment |
$begingroup$
I have a dict
x = 'a':[1,2,3], 'b':[4,5,6]
and I have to extract a key based on an input, in this case assume it is 3
So my output should be a
Here's my code:
x = 'a':[1,2,3], 'b':[4,5,6]
n = 3
output = [k for k,v in x.items() if n in v]
print(output[0])
Can it be done more efficiently?
Elements in the lists are uniques. eg. value 3 will only be in one list.
python python-3.x
asked 7 mins ago
AkshayNevrekarAkshayNevrekar
1205
$endgroup$
I have a dict
x = 'a':[1,2,3], 'b':[4,5,6]
and I have to extract a key based on an input, in this case assume it is 3
So my output should be a
Here's my code:
x = 'a':[1,2,3], 'b':[4,5,6]
n = 3
output = [k for k,v in x.items() if n in v]
print(output[0])
Can it be done more efficiently?
Elements in the lists are uniques. eg. value 3 will only be in one list.
python python-3.x
python python-3.x
asked 7 mins ago
AkshayNevrekarAkshayNevrekar
1205
asked 7 mins ago
AkshayNevrekarAkshayNevrekar
1205
asked 7 mins ago
AkshayNevrekarAkshayNevrekar
1205
asked 7 mins ago
AkshayNevrekarAkshayNevrekar
1205
asked 7 mins ago
AkshayNevrekarAkshayNevrekar
1205
1205
add a comment |
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "196"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
var $window = $(window),
onScroll = function(e)
var $elem = $('.new-login-left'),
docViewTop = $window.scrollTop(),
docViewBottom = docViewTop + $window.height(),
elemTop = $elem.offset().top,
elemBottom = elemTop + $elem.height();
if ((docViewTop elemBottom))
StackExchange.using('gps', function() StackExchange.gps.track('embedded_signup_form.view', location: 'question_page' ); );
$window.unbind('scroll', onScroll);
;
$window.on('scroll', onScroll);
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f217874%2ffinding-a-key-from-valueswhich-are-list-in-dict%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Code Review Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
var $window = $(window),
onScroll = function(e)
var $elem = $('.new-login-left'),
docViewTop = $window.scrollTop(),
docViewBottom = docViewTop + $window.height(),
elemTop = $elem.offset().top,
elemBottom = elemTop + $elem.height();
if ((docViewTop elemBottom))
StackExchange.using('gps', function() StackExchange.gps.track('embedded_signup_form.view', location: 'question_page' ); );
$window.unbind('scroll', onScroll);
;
$window.on('scroll', onScroll);
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f217874%2ffinding-a-key-from-valueswhich-are-list-in-dict%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
var $window = $(window),
onScroll = function(e)
var $elem = $('.new-login-left'),
docViewTop = $window.scrollTop(),
docViewBottom = docViewTop + $window.height(),
elemTop = $elem.offset().top,
elemBottom = elemTop + $elem.height();
if ((docViewTop elemBottom))
StackExchange.using('gps', function() StackExchange.gps.track('embedded_signup_form.view', location: 'question_page' ); );
$window.unbind('scroll', onScroll);
;
$window.on('scroll', onScroll);
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
var $window = $(window),
onScroll = function(e)
var $elem = $('.new-login-left'),
docViewTop = $window.scrollTop(),
docViewBottom = docViewTop + $window.height(),
elemTop = $elem.offset().top,
elemBottom = elemTop + $elem.height();
if ((docViewTop elemBottom))
StackExchange.using('gps', function() StackExchange.gps.track('embedded_signup_form.view', location: 'question_page' ); );
$window.unbind('scroll', onScroll);
;
$window.on('scroll', onScroll);
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
var $window = $(window),
onScroll = function(e)
var $elem = $('.new-login-left'),
docViewTop = $window.scrollTop(),
docViewBottom = docViewTop + $window.height(),
elemTop = $elem.offset().top,
elemBottom = elemTop + $elem.height();
if ((docViewTop elemBottom))
StackExchange.using('gps', function() StackExchange.gps.track('embedded_signup_form.view', location: 'question_page' ); );
$window.unbind('scroll', onScroll);
;
$window.on('scroll', onScroll);
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
