N-Repeated Element in Size 2N Array Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern) Announcing the arrival of Valued Associate #679: Cesar Manara Unicorn Meta Zoo #1: Why another podcast?Testing if numbers in the array can be added up to equal the largest number in the arrayHacker Rank - Lonely IntegerPassword Attacker (Google apac test problem)ADDREV - Adding Reversed NumbersArray partition 1 to group the array into pairs and make sum of minimum of pairs as maximumMinimum Area Rectangle in SwiftGiven a set of closed intervals, find the smallest set of numbers that covers all the intervalsIn an set of integers, find three elements summing to zero (3-sum, leetcode variant)Leetcode online Find the judge, graph with highest degreeFind indices of two numbers such that they add up to a target
Marquee sign letters
IC on Digikey is 5x more expensive than board containing same IC on Alibaba: How?
Did pre-Columbian Americans know the spherical shape of the Earth?
Keep at all times, the minus sign above aligned with minus sign below
Can two people see the same photon?
Dinosaur Word Search, Letter Solve, and Unscramble
By what mechanism was the 2017 UK General Election called?
How do Java 8 default methods hеlp with lambdas?
Noise in Eigenvalues plot
The Nth Gryphon Number
Is a copyright notice with a non-existent name be invalid?
How do I find my Spellcasting Ability for my D&D character?
Is there a canonical “inverse” of Abelianization?
Why do C and C++ allow the expression (int) + 4*5?
The test team as an enemy of development? And how can this be avoided?
One-one communication
Can I cut the hair of a conjured korred with a blade made of precious material to harvest that material from the korred?
malloc in main() or malloc in another function: allocating memory for a struct and its members
New Order #6: Easter Egg
Plotting a Maclaurin series
Can a Knight grant Knighthood to another?
Where did Ptolemy compare the Earth to the distance of fixed stars?
Does the universe have a fixed centre of mass?
Understanding piped commands in GNU/Linux
N-Repeated Element in Size 2N Array
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)
Announcing the arrival of Valued Associate #679: Cesar Manara
Unicorn Meta Zoo #1: Why another podcast?Testing if numbers in the array can be added up to equal the largest number in the arrayHacker Rank - Lonely IntegerPassword Attacker (Google apac test problem)ADDREV - Adding Reversed NumbersArray partition 1 to group the array into pairs and make sum of minimum of pairs as maximumMinimum Area Rectangle in SwiftGiven a set of closed intervals, find the smallest set of numbers that covers all the intervalsIn an set of integers, find three elements summing to zero (3-sum, leetcode variant)Leetcode online Find the judge, graph with highest degreeFind indices of two numbers such that they add up to a target
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
$begingroup$
The task
is taken from leetcode
In a array A of size 2N, there are N+1 unique elements, and exactly
one of these elements is repeated N times.
Return the element repeated N times.
Example 1:
Input: [1,2,3,3] Output: 3
Example 2:
Input: [2,1,2,5,3,2] Output: 2
Example 3:
Input: [5,1,5,2,5,3,5,4] Output: 5
Note:
4 <= A.length <= 10000 0 <= A[i] < 10000 A.length is even
My solution
var repeatedNTimes = function(A)
const set = new Set();
for (const n of A)
if (set.has(n))
return n;
else
set.add(n);
;
I didn't do much with the information size 2N, there are N+1 unique elements, and exactly one of these elements is repeated N times. I think these information is not needed to solve the problem efficiently. I also wonder whether there is a bitwise or purely math based solution to the task.
javascript algorithm programming-challenge ecmascript-6
asked 23 mins ago
thadeuszlaythadeuszlay
1,002616
$endgroup$
add a comment |
$begingroup$
The task
is taken from leetcode
In a array A of size 2N, there are N+1 unique elements, and exactly
one of these elements is repeated N times.
Return the element repeated N times.
Example 1:
Input: [1,2,3,3] Output: 3
Example 2:
Input: [2,1,2,5,3,2] Output: 2
Example 3:
Input: [5,1,5,2,5,3,5,4] Output: 5
Note:
4 <= A.length <= 10000 0 <= A[i] < 10000 A.length is even
My solution
var repeatedNTimes = function(A)
const set = new Set();
for (const n of A)
if (set.has(n))
return n;
else
set.add(n);
;
I didn't do much with the information size 2N, there are N+1 unique elements, and exactly one of these elements is repeated N times. I think these information is not needed to solve the problem efficiently. I also wonder whether there is a bitwise or purely math based solution to the task.
javascript algorithm programming-challenge ecmascript-6
asked 23 mins ago
thadeuszlaythadeuszlay
1,002616
$endgroup$
add a comment |
$begingroup$
The task
is taken from leetcode
In a array A of size 2N, there are N+1 unique elements, and exactly
one of these elements is repeated N times.
Return the element repeated N times.
Example 1:
Input: [1,2,3,3] Output: 3
Example 2:
Input: [2,1,2,5,3,2] Output: 2
Example 3:
Input: [5,1,5,2,5,3,5,4] Output: 5
Note:
4 <= A.length <= 10000 0 <= A[i] < 10000 A.length is even
My solution
var repeatedNTimes = function(A)
const set = new Set();
for (const n of A)
if (set.has(n))
return n;
else
set.add(n);
;
I didn't do much with the information size 2N, there are N+1 unique elements, and exactly one of these elements is repeated N times. I think these information is not needed to solve the problem efficiently. I also wonder whether there is a bitwise or purely math based solution to the task.
javascript algorithm programming-challenge ecmascript-6
asked 23 mins ago
thadeuszlaythadeuszlay
1,002616
$endgroup$
The task
is taken from leetcode
In a array A of size 2N, there are N+1 unique elements, and exactly
one of these elements is repeated N times.
Return the element repeated N times.
Example 1:
Input: [1,2,3,3] Output: 3
Example 2:
Input: [2,1,2,5,3,2] Output: 2
Example 3:
Input: [5,1,5,2,5,3,5,4] Output: 5
Note:
4 <= A.length <= 10000 0 <= A[i] < 10000 A.length is even
My solution
var repeatedNTimes = function(A)
const set = new Set();
for (const n of A)
if (set.has(n))
return n;
else
set.add(n);
;
I didn't do much with the information size 2N, there are N+1 unique elements, and exactly one of these elements is repeated N times. I think these information is not needed to solve the problem efficiently. I also wonder whether there is a bitwise or purely math based solution to the task.
javascript algorithm programming-challenge ecmascript-6
javascript algorithm programming-challenge ecmascript-6
asked 23 mins ago
thadeuszlaythadeuszlay
1,002616
asked 23 mins ago
thadeuszlaythadeuszlay
1,002616
edited 8 mins ago
thadeuszlay
asked 23 mins ago
thadeuszlaythadeuszlay
1,002616
asked 23 mins ago
thadeuszlaythadeuszlay
1,002616
asked 23 mins ago
thadeuszlaythadeuszlay
1,002616
1,002616
add a comment |
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "196"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
var $window = $(window),
onScroll = function(e)
var $elem = $('.new-login-left'),
docViewTop = $window.scrollTop(),
docViewBottom = docViewTop + $window.height(),
elemTop = $elem.offset().top,
elemBottom = elemTop + $elem.height();
if ((docViewTop elemBottom))
StackExchange.using('gps', function() StackExchange.gps.track('embedded_signup_form.view', location: 'question_page' ); );
$window.unbind('scroll', onScroll);
;
$window.on('scroll', onScroll);
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f217877%2fn-repeated-element-in-size-2n-array%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Code Review Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
var $window = $(window),
onScroll = function(e)
var $elem = $('.new-login-left'),
docViewTop = $window.scrollTop(),
docViewBottom = docViewTop + $window.height(),
elemTop = $elem.offset().top,
elemBottom = elemTop + $elem.height();
if ((docViewTop elemBottom))
StackExchange.using('gps', function() StackExchange.gps.track('embedded_signup_form.view', location: 'question_page' ); );
$window.unbind('scroll', onScroll);
;
$window.on('scroll', onScroll);
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f217877%2fn-repeated-element-in-size-2n-array%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
var $window = $(window),
onScroll = function(e)
var $elem = $('.new-login-left'),
docViewTop = $window.scrollTop(),
docViewBottom = docViewTop + $window.height(),
elemTop = $elem.offset().top,
elemBottom = elemTop + $elem.height();
if ((docViewTop elemBottom))
StackExchange.using('gps', function() StackExchange.gps.track('embedded_signup_form.view', location: 'question_page' ); );
$window.unbind('scroll', onScroll);
;
$window.on('scroll', onScroll);
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
var $window = $(window),
onScroll = function(e)
var $elem = $('.new-login-left'),
docViewTop = $window.scrollTop(),
docViewBottom = docViewTop + $window.height(),
elemTop = $elem.offset().top,
elemBottom = elemTop + $elem.height();
if ((docViewTop elemBottom))
StackExchange.using('gps', function() StackExchange.gps.track('embedded_signup_form.view', location: 'question_page' ); );
$window.unbind('scroll', onScroll);
;
$window.on('scroll', onScroll);
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
var $window = $(window),
onScroll = function(e)
var $elem = $('.new-login-left'),
docViewTop = $window.scrollTop(),
docViewBottom = docViewTop + $window.height(),
elemTop = $elem.offset().top,
elemBottom = elemTop + $elem.height();
if ((docViewTop elemBottom))
StackExchange.using('gps', function() StackExchange.gps.track('embedded_signup_form.view', location: 'question_page' ); );
$window.unbind('scroll', onScroll);
;
$window.on('scroll', onScroll);
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
