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-1

$begingroup$

so i gotta create this sliding block game for an assignment and part of the assignment is i have to track where the blocks are in the game and the plan was to create a list of all RGB values of each block and give them separate names such as list 0, list 1 etc. im wondering is this a good way to do it? will the program be really slow if i do it this way? and is there a better way? this is the section of code dedicated to making the lists. the def numbers()

```python
def numbers():
 list0 = []#creates an empty list
 for x in range(0, getWidth(canvas)/4):
 for y in range(0, getHeight(canvas)/4):
 pic0 = getPixel(canvas, x, y)
 list0.append([pic0])#collects all the pixels in the first square of the #grid and puts them into the 'list0' 
 list1 = []
 for x in range(getWidth(canvas)/4, getWidth(canvas)*2/4):
 for y in range(0, getHeight(canvas)/4):
 pic1 = getPixel(canvas, x, y)
 list1.append([pic1])
 list2 = []
 for x in range(getWidth(canvas)*2/4, getWidth(canvas)*3/4):
 for y in range(0, getHeight(canvas)/4):
 pic2 = getPixel(canvas, x, y)
 list2.append([pic2])

and this is the overall code:

btw the def test() at the end is just me making sure i have the right segment of pixels on the picture before i append the RGB values into a list on def numbers().
thanks

python jython

share|improve this question

asked 12 mins ago

Ewan SimpsonEwan Simpson

1

New contributor

Ewan Simpson is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Please do not post code as screenshots.
  $endgroup$
  – 200_success
  2 mins ago
  

  
  
  
  

add a comment | 

-1

$begingroup$

so i gotta create this sliding block game for an assignment and part of the assignment is i have to track where the blocks are in the game and the plan was to create a list of all RGB values of each block and give them separate names such as list 0, list 1 etc. im wondering is this a good way to do it? will the program be really slow if i do it this way? and is there a better way? this is the section of code dedicated to making the lists. the def numbers()

```python
def numbers():
 list0 = []#creates an empty list
 for x in range(0, getWidth(canvas)/4):
 for y in range(0, getHeight(canvas)/4):
 pic0 = getPixel(canvas, x, y)
 list0.append([pic0])#collects all the pixels in the first square of the #grid and puts them into the 'list0' 
 list1 = []
 for x in range(getWidth(canvas)/4, getWidth(canvas)*2/4):
 for y in range(0, getHeight(canvas)/4):
 pic1 = getPixel(canvas, x, y)
 list1.append([pic1])
 list2 = []
 for x in range(getWidth(canvas)*2/4, getWidth(canvas)*3/4):
 for y in range(0, getHeight(canvas)/4):
 pic2 = getPixel(canvas, x, y)
 list2.append([pic2])

and this is the overall code:

btw the def test() at the end is just me making sure i have the right segment of pixels on the picture before i append the RGB values into a list on def numbers().
thanks

python jython

share|improve this question

asked 12 mins ago

Ewan SimpsonEwan Simpson

1

New contributor

Ewan Simpson is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Please do not post code as screenshots.
  $endgroup$
  – 200_success
  2 mins ago
  

  
  
  
  

add a comment | 

$begingroup$

so i gotta create this sliding block game for an assignment and part of the assignment is i have to track where the blocks are in the game and the plan was to create a list of all RGB values of each block and give them separate names such as list 0, list 1 etc. im wondering is this a good way to do it? will the program be really slow if i do it this way? and is there a better way? this is the section of code dedicated to making the lists. the def numbers()

```python
def numbers():
 list0 = []#creates an empty list
 for x in range(0, getWidth(canvas)/4):
 for y in range(0, getHeight(canvas)/4):
 pic0 = getPixel(canvas, x, y)
 list0.append([pic0])#collects all the pixels in the first square of the #grid and puts them into the 'list0' 
 list1 = []
 for x in range(getWidth(canvas)/4, getWidth(canvas)*2/4):
 for y in range(0, getHeight(canvas)/4):
 pic1 = getPixel(canvas, x, y)
 list1.append([pic1])
 list2 = []
 for x in range(getWidth(canvas)*2/4, getWidth(canvas)*3/4):
 for y in range(0, getHeight(canvas)/4):
 pic2 = getPixel(canvas, x, y)
 list2.append([pic2])

and this is the overall code:

btw the def test() at the end is just me making sure i have the right segment of pixels on the picture before i append the RGB values into a list on def numbers().
thanks

python jython

share|improve this question

asked 12 mins ago

Ewan SimpsonEwan Simpson

1

New contributor

Ewan Simpson is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

```python
def numbers():
 list0 = []#creates an empty list
 for x in range(0, getWidth(canvas)/4):
 for y in range(0, getHeight(canvas)/4):
 pic0 = getPixel(canvas, x, y)
 list0.append([pic0])#collects all the pixels in the first square of the #grid and puts them into the 'list0' 
 list1 = []
 for x in range(getWidth(canvas)/4, getWidth(canvas)*2/4):
 for y in range(0, getHeight(canvas)/4):
 pic1 = getPixel(canvas, x, y)
 list1.append([pic1])
 list2 = []
 for x in range(getWidth(canvas)*2/4, getWidth(canvas)*3/4):
 for y in range(0, getHeight(canvas)/4):
 pic2 = getPixel(canvas, x, y)
 list2.append([pic2])

share|improve this question

asked 12 mins ago

Ewan SimpsonEwan Simpson

1

New contributor

Ewan Simpson is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

asked 12 mins ago

Ewan SimpsonEwan Simpson

1

New contributor

Ewan Simpson is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 12 mins ago

Ewan SimpsonEwan Simpson

1

New contributor

Ewan Simpson is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 12 mins ago

Ewan SimpsonEwan Simpson

1