Finding nth lowest value without any Math max or min methodsFinding the pairs of intersecting discsCalculating the Nth number in the supertable of two numbersThe longest subsequence with specified difference between min and maxArray is MinMax Equal or NotFinding the longest sequence of positive numbers in integer arrayChecking whether the max and min values occur equally frequently“Max Min” in HackerRankgroupArray() - Convert flat array into multidimensional array by groupCalculate min, max, mean and median out of arrayCalculate min, max, mean and median out of array Version 2

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Finding nth lowest value without any Math max or min methods


Finding the pairs of intersecting discsCalculating the Nth number in the supertable of two numbersThe longest subsequence with specified difference between min and maxArray is MinMax Equal or NotFinding the longest sequence of positive numbers in integer arrayChecking whether the max and min values occur equally frequently“Max Min” in HackerRankgroupArray() - Convert flat array into multidimensional array by groupCalculate min, max, mean and median out of arrayCalculate min, max, mean and median out of array Version 2













0












$begingroup$


So I decided to make a more efficient solution to a Google interview question where they ask you to either find the lowest or second lowest value in an array without using the max or min methods. I believe it is more efficient because you can use my method to find any nth lowest value in the array so it solves for all cases.



Please let me know if there is anything I can do to improve this solution or if there is anything I am missing:



/*Algorithm:
-first sort the array from ascending order
-Then iterate over the array with a loop
-if(array[i + nth lowest input you want])
-return the output

function nThOrderStatistic(array, number):
-if you want to find the lowest number sub in 0 for number
-for every nth lowest you want sub in n - 1 for the number */


function nThOrderStatistic(array, number)
array.sort(function(a,b)return a -b);
for(i = 0; i < array.length; i++)

if(array[i + number] < array[i + (number + 1)])

return array[i + number];




nThOrderStatistic([6,7,43,2,95], 2);

//sample output for 3rd lowest value is: 7 //








share









$endgroup$
















    0












    $begingroup$


    So I decided to make a more efficient solution to a Google interview question where they ask you to either find the lowest or second lowest value in an array without using the max or min methods. I believe it is more efficient because you can use my method to find any nth lowest value in the array so it solves for all cases.



    Please let me know if there is anything I can do to improve this solution or if there is anything I am missing:



    /*Algorithm:
    -first sort the array from ascending order
    -Then iterate over the array with a loop
    -if(array[i + nth lowest input you want])
    -return the output

    function nThOrderStatistic(array, number):
    -if you want to find the lowest number sub in 0 for number
    -for every nth lowest you want sub in n - 1 for the number */


    function nThOrderStatistic(array, number)
    array.sort(function(a,b)return a -b);
    for(i = 0; i < array.length; i++)

    if(array[i + number] < array[i + (number + 1)])

    return array[i + number];




    nThOrderStatistic([6,7,43,2,95], 2);

    //sample output for 3rd lowest value is: 7 //








    share









    $endgroup$














      0












      0








      0





      $begingroup$


      So I decided to make a more efficient solution to a Google interview question where they ask you to either find the lowest or second lowest value in an array without using the max or min methods. I believe it is more efficient because you can use my method to find any nth lowest value in the array so it solves for all cases.



      Please let me know if there is anything I can do to improve this solution or if there is anything I am missing:



      /*Algorithm:
      -first sort the array from ascending order
      -Then iterate over the array with a loop
      -if(array[i + nth lowest input you want])
      -return the output

      function nThOrderStatistic(array, number):
      -if you want to find the lowest number sub in 0 for number
      -for every nth lowest you want sub in n - 1 for the number */


      function nThOrderStatistic(array, number)
      array.sort(function(a,b)return a -b);
      for(i = 0; i < array.length; i++)

      if(array[i + number] < array[i + (number + 1)])

      return array[i + number];




      nThOrderStatistic([6,7,43,2,95], 2);

      //sample output for 3rd lowest value is: 7 //








      share









      $endgroup$




      So I decided to make a more efficient solution to a Google interview question where they ask you to either find the lowest or second lowest value in an array without using the max or min methods. I believe it is more efficient because you can use my method to find any nth lowest value in the array so it solves for all cases.



      Please let me know if there is anything I can do to improve this solution or if there is anything I am missing:



      /*Algorithm:
      -first sort the array from ascending order
      -Then iterate over the array with a loop
      -if(array[i + nth lowest input you want])
      -return the output

      function nThOrderStatistic(array, number):
      -if you want to find the lowest number sub in 0 for number
      -for every nth lowest you want sub in n - 1 for the number */


      function nThOrderStatistic(array, number)
      array.sort(function(a,b)return a -b);
      for(i = 0; i < array.length; i++)

      if(array[i + number] < array[i + (number + 1)])

      return array[i + number];




      nThOrderStatistic([6,7,43,2,95], 2);

      //sample output for 3rd lowest value is: 7 //






      javascript algorithm programming-challenge array functional-programming





      share












      share










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      asked 6 mins ago









      DreamVision2017DreamVision2017

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