How to alter function so it won't be on the one line but be curved using matplotlib?
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How to alter function so it won't be on the one line but be curved using matplotlib?
0
$begingroup$
I have that code:
from matplotlib import pyplot as plt
import numpy as np
halflife = 0.25
resolution_per_second = 1000
values = np.concatenate([np.zeros(resolution_per_second),
np.ones(resolution_per_second * 2),
np.zeros(resolution_per_second),
np.ones(resolution_per_second * 1),
np.zeros(resolution_per_second * 2),
])
t_grid = np.arange(0, len(values)) / resolution_per_second
step = 1.0 / resolution_per_second
k = np.power(0.5, 1 / (halflife * resolution_per_second))
def ema_fixed_step(y, k): #ema method 1 on chart
res = np.zeros_like(y)
curV = y[0]
for i in range(1, len(y) - 1):
curV = k * curV + (1 - k) * y[i]
res[i + 1] = curV
return res
ema1_arr = ema_fixed_step(values, k)
#
w = values != np.roll(values, 1)
w[0] = True
t_new = t_grid[w]
values_new = values[w]
t_extra = [0.6, 1.0001, 1.2, 1.5, 2.9, 4.5, 3.3, 5.5]
t_req = np.sort(np.concatenate([t_new, t_extra]))
def ema_func2(t_req, t, y): #ema method 2 on chart
return np.zeros_like(t_req, dtype=np.double)
ema2_arr = ema_func2(t_req, t_new, values_new)
plt.clf()
plt.step(t_grid, values, '.-', where='post', label='y')
plt.step(t_grid, ema1_arr, '.-', where='post', label='ema method 1')
plt.plot(t_req, ema2_arr, 'o', color='red', markersize=4, label='ema method 2')
plt.grid()
plt.legend()
plt.xlabel('t, seconds')
That's the part of code and that's the result:
I need to complete ema_func2 so the dots would be on the orange line. How is it possible to complete function for those red dots appear on the orange curve. So, I need to take some piece from ema_fixed_step and somehow alter it according to t_req. How could it be done?
python data-visualization matplotlib
asked 1 min ago
SomeOneInterestingSomeOneInteresting
1
New contributor
SomeOneInteresting is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
0
$begingroup$
I have that code:
from matplotlib import pyplot as plt
import numpy as np
halflife = 0.25
resolution_per_second = 1000
values = np.concatenate([np.zeros(resolution_per_second),
np.ones(resolution_per_second * 2),
np.zeros(resolution_per_second),
np.ones(resolution_per_second * 1),
np.zeros(resolution_per_second * 2),
])
t_grid = np.arange(0, len(values)) / resolution_per_second
step = 1.0 / resolution_per_second
k = np.power(0.5, 1 / (halflife * resolution_per_second))
def ema_fixed_step(y, k): #ema method 1 on chart
res = np.zeros_like(y)
curV = y[0]
for i in range(1, len(y) - 1):
curV = k * curV + (1 - k) * y[i]
res[i + 1] = curV
return res
ema1_arr = ema_fixed_step(values, k)
#
w = values != np.roll(values, 1)
w[0] = True
t_new = t_grid[w]
values_new = values[w]
t_extra = [0.6, 1.0001, 1.2, 1.5, 2.9, 4.5, 3.3, 5.5]
t_req = np.sort(np.concatenate([t_new, t_extra]))
def ema_func2(t_req, t, y): #ema method 2 on chart
return np.zeros_like(t_req, dtype=np.double)
ema2_arr = ema_func2(t_req, t_new, values_new)
plt.clf()
plt.step(t_grid, values, '.-', where='post', label='y')
plt.step(t_grid, ema1_arr, '.-', where='post', label='ema method 1')
plt.plot(t_req, ema2_arr, 'o', color='red', markersize=4, label='ema method 2')
plt.grid()
plt.legend()
plt.xlabel('t, seconds')
That's the part of code and that's the result:
I need to complete ema_func2 so the dots would be on the orange line. How is it possible to complete function for those red dots appear on the orange curve. So, I need to take some piece from ema_fixed_step and somehow alter it according to t_req. How could it be done?
python data-visualization matplotlib
asked 1 min ago
SomeOneInterestingSomeOneInteresting
1
New contributor
SomeOneInteresting is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
0
0
0
$begingroup$
I have that code:
from matplotlib import pyplot as plt
import numpy as np
halflife = 0.25
resolution_per_second = 1000
values = np.concatenate([np.zeros(resolution_per_second),
np.ones(resolution_per_second * 2),
np.zeros(resolution_per_second),
np.ones(resolution_per_second * 1),
np.zeros(resolution_per_second * 2),
])
t_grid = np.arange(0, len(values)) / resolution_per_second
step = 1.0 / resolution_per_second
k = np.power(0.5, 1 / (halflife * resolution_per_second))
def ema_fixed_step(y, k): #ema method 1 on chart
res = np.zeros_like(y)
curV = y[0]
for i in range(1, len(y) - 1):
curV = k * curV + (1 - k) * y[i]
res[i + 1] = curV
return res
ema1_arr = ema_fixed_step(values, k)
#
w = values != np.roll(values, 1)
w[0] = True
t_new = t_grid[w]
values_new = values[w]
t_extra = [0.6, 1.0001, 1.2, 1.5, 2.9, 4.5, 3.3, 5.5]
t_req = np.sort(np.concatenate([t_new, t_extra]))
def ema_func2(t_req, t, y): #ema method 2 on chart
return np.zeros_like(t_req, dtype=np.double)
ema2_arr = ema_func2(t_req, t_new, values_new)
plt.clf()
plt.step(t_grid, values, '.-', where='post', label='y')
plt.step(t_grid, ema1_arr, '.-', where='post', label='ema method 1')
plt.plot(t_req, ema2_arr, 'o', color='red', markersize=4, label='ema method 2')
plt.grid()
plt.legend()
plt.xlabel('t, seconds')
That's the part of code and that's the result:
I need to complete ema_func2 so the dots would be on the orange line. How is it possible to complete function for those red dots appear on the orange curve. So, I need to take some piece from ema_fixed_step and somehow alter it according to t_req. How could it be done?
python data-visualization matplotlib
asked 1 min ago
SomeOneInterestingSomeOneInteresting
1
New contributor
SomeOneInteresting is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I have that code:
from matplotlib import pyplot as plt
import numpy as np
halflife = 0.25
resolution_per_second = 1000
values = np.concatenate([np.zeros(resolution_per_second),
np.ones(resolution_per_second * 2),
np.zeros(resolution_per_second),
np.ones(resolution_per_second * 1),
np.zeros(resolution_per_second * 2),
])
t_grid = np.arange(0, len(values)) / resolution_per_second
step = 1.0 / resolution_per_second
k = np.power(0.5, 1 / (halflife * resolution_per_second))
def ema_fixed_step(y, k): #ema method 1 on chart
res = np.zeros_like(y)
curV = y[0]
for i in range(1, len(y) - 1):
curV = k * curV + (1 - k) * y[i]
res[i + 1] = curV
return res
ema1_arr = ema_fixed_step(values, k)
#
w = values != np.roll(values, 1)
w[0] = True
t_new = t_grid[w]
values_new = values[w]
t_extra = [0.6, 1.0001, 1.2, 1.5, 2.9, 4.5, 3.3, 5.5]
t_req = np.sort(np.concatenate([t_new, t_extra]))
def ema_func2(t_req, t, y): #ema method 2 on chart
return np.zeros_like(t_req, dtype=np.double)
ema2_arr = ema_func2(t_req, t_new, values_new)
plt.clf()
plt.step(t_grid, values, '.-', where='post', label='y')
plt.step(t_grid, ema1_arr, '.-', where='post', label='ema method 1')
plt.plot(t_req, ema2_arr, 'o', color='red', markersize=4, label='ema method 2')
plt.grid()
plt.legend()
plt.xlabel('t, seconds')
That's the part of code and that's the result:
I need to complete ema_func2 so the dots would be on the orange line. How is it possible to complete function for those red dots appear on the orange curve. So, I need to take some piece from ema_fixed_step and somehow alter it according to t_req. How could it be done?
python data-visualization matplotlib
python data-visualization matplotlib
asked 1 min ago
SomeOneInterestingSomeOneInteresting
1
New contributor
SomeOneInteresting is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 1 min ago
SomeOneInterestingSomeOneInteresting
1
New contributor
SomeOneInteresting is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 1 min ago
SomeOneInterestingSomeOneInteresting
1
New contributor
SomeOneInteresting is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 1 min ago
SomeOneInterestingSomeOneInteresting
1
asked 1 min ago
SomeOneInterestingSomeOneInteresting
1
1
New contributor
SomeOneInteresting is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
SomeOneInteresting is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
SomeOneInteresting is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
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