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Finding multiple roots of a curve

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-2

$begingroup$

I need to find the lower and upper intersections with the x axis of a curve given by

y=f(x)= 10*e^(sin(x)) - (x^2)/2

I have found the value of one root, but I don't know how to change my code to find another.

from math import exp 
from math import sin
from math import cos

def func( x ): 
 return 10*exp(sin(x))-(x**2)/2

def derivFunc( x ): 
 return 10*exp(sin(x))*cos(x)-x

def newtonRaphson( x ): 
 h = func(x) / derivFunc(x) 
 while abs(h) >= 0.0001: 
 h = func(x)/derivFunc(x) 

 x = x - h 

 print("The value of the root is : ", 
 "%.4f"% x) 


x0 = -20 
newtonRaphson(x0) 

I've been told another way is to use something called the Secant Method but I don't know how to do that.
Any help will be much appreciated

python python-3.x numerical-methods

share|improve this question

asked 26 mins ago

JuhBuhJuhBuh

1

New contributor

JuhBuh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

add a comment | 

-2

$begingroup$

I need to find the lower and upper intersections with the x axis of a curve given by

y=f(x)= 10*e^(sin(x)) - (x^2)/2

I have found the value of one root, but I don't know how to change my code to find another.

from math import exp 
from math import sin
from math import cos

def func( x ): 
 return 10*exp(sin(x))-(x**2)/2

def derivFunc( x ): 
 return 10*exp(sin(x))*cos(x)-x

def newtonRaphson( x ): 
 h = func(x) / derivFunc(x) 
 while abs(h) >= 0.0001: 
 h = func(x)/derivFunc(x) 

 x = x - h 

 print("The value of the root is : ", 
 "%.4f"% x) 


x0 = -20 
newtonRaphson(x0) 

I've been told another way is to use something called the Secant Method but I don't know how to do that.
Any help will be much appreciated

python python-3.x numerical-methods

share|improve this question

asked 26 mins ago

JuhBuhJuhBuh

1

New contributor

JuhBuh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

add a comment | 

$begingroup$

I need to find the lower and upper intersections with the x axis of a curve given by

y=f(x)= 10*e^(sin(x)) - (x^2)/2

I have found the value of one root, but I don't know how to change my code to find another.

from math import exp 
from math import sin
from math import cos

def func( x ): 
 return 10*exp(sin(x))-(x**2)/2

def derivFunc( x ): 
 return 10*exp(sin(x))*cos(x)-x

def newtonRaphson( x ): 
 h = func(x) / derivFunc(x) 
 while abs(h) >= 0.0001: 
 h = func(x)/derivFunc(x) 

 x = x - h 

 print("The value of the root is : ", 
 "%.4f"% x) 


x0 = -20 
newtonRaphson(x0) 

I've been told another way is to use something called the Secant Method but I don't know how to do that.
Any help will be much appreciated

python python-3.x numerical-methods

share|improve this question

asked 26 mins ago

JuhBuhJuhBuh

1

New contributor

JuhBuh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

from math import exp 
from math import sin
from math import cos

def func( x ): 
 return 10*exp(sin(x))-(x**2)/2

def derivFunc( x ): 
 return 10*exp(sin(x))*cos(x)-x

def newtonRaphson( x ): 
 h = func(x) / derivFunc(x) 
 while abs(h) >= 0.0001: 
 h = func(x)/derivFunc(x) 

 x = x - h 

 print("The value of the root is : ", 
 "%.4f"% x) 


x0 = -20 
newtonRaphson(x0) 

share|improve this question

asked 26 mins ago

JuhBuhJuhBuh

1

New contributor

JuhBuh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

asked 26 mins ago

JuhBuhJuhBuh

1

New contributor

JuhBuh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 26 mins ago

JuhBuhJuhBuh

1

New contributor

JuhBuh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 26 mins ago

JuhBuhJuhBuh

1