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My code is an advanced love calculator that generates a result based on the similarities between the two names. Is this correct?

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$begingroup$

My love calculator gives a result from 0 to 100% based on these factors:

1. If the first letters of the names are the same.


2. If the number of vowels is the same.


3. If the length of the name is the same.


4. If the number of consonants is the same.

Also, there is an extra boost of 10-50%, so the result is also partially as a result of luck.
Can the coding below be simplified or improved to function more smoothly?:

name1 = input("Please type Name 1.n")
name2 = input("Please type Name 2.n")

total_vowel1 =0
for i in ['a','e','i','o','u']:
 total_vowel1 += name1.count(i)
total_vowel2 =0
for i in ['a','e','i','o','u']:
 total_vowel2 += name2.count(i)

love = 0
if(total_vowel1 == total_vowel2):
 import random
 love +=random.randint(10,30)

consonants1 = 0
consonants2 = 0
CONSONANTS = 'bcdfghjklmnprstvwxyz'
consonants1 = len([letter for letter in name1 if letter.lower() in 
CONSONANTS])
consonants2 = len([letter for letter in name2 if letter.lower() in 
CONSONANTS])

if(consonants1 == consonants2):
 import random
 love +=random.randint(20,40)

line1 = name1
line2 = name2
split1 = line1.split()
split2 = line2.split()
fl1 = [word[0] for word in split1]
fl2 = [word[0] for word in split2]

if (fl1 == fl2):
 import random
 love +=random.randint(10,30)

if (len(name1) == len(name2)):
 import random
 love+=random.randint(1,10)

import random
love +=random.randint(10,50)
if (love>100):
 love = 100

print("Calculating...")
import time
import random
time.sleep(random.randint(1,3))

print("",name1,"and",name2,"have a",love,"% relationship.")
if ((love>90) or (love == 90)):
 print("They have an unbreakable relationship that will last 
 forever.")
if ((love<89) or (love == 89)) and ((love>70) or (love == 70)):
 print("They have a strong relationship that will most likely 
 lead to a marriage.")
if ((love<69) or (love == 69)) and ((love>50) or (love == 50)):
 print("They have a good relationship that can lead to a 
 honeymoon to Paris.")
if ((love<49) or (love == 49)):
 print("They have a weak relationship that could have been a 
 'match made in heaven'.")

python calculator generator

share

asked 3 mins ago

MustafaMustafa

11

New contributor

Mustafa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

add a comment | 

0

$begingroup$

My love calculator gives a result from 0 to 100% based on these factors:

1. If the first letters of the names are the same.


2. If the number of vowels is the same.


3. If the length of the name is the same.


4. If the number of consonants is the same.

Also, there is an extra boost of 10-50%, so the result is also partially as a result of luck.
Can the coding below be simplified or improved to function more smoothly?:

name1 = input("Please type Name 1.n")
name2 = input("Please type Name 2.n")

total_vowel1 =0
for i in ['a','e','i','o','u']:
 total_vowel1 += name1.count(i)
total_vowel2 =0
for i in ['a','e','i','o','u']:
 total_vowel2 += name2.count(i)

love = 0
if(total_vowel1 == total_vowel2):
 import random
 love +=random.randint(10,30)

consonants1 = 0
consonants2 = 0
CONSONANTS = 'bcdfghjklmnprstvwxyz'
consonants1 = len([letter for letter in name1 if letter.lower() in 
CONSONANTS])
consonants2 = len([letter for letter in name2 if letter.lower() in 
CONSONANTS])

if(consonants1 == consonants2):
 import random
 love +=random.randint(20,40)

line1 = name1
line2 = name2
split1 = line1.split()
split2 = line2.split()
fl1 = [word[0] for word in split1]
fl2 = [word[0] for word in split2]

if (fl1 == fl2):
 import random
 love +=random.randint(10,30)

if (len(name1) == len(name2)):
 import random
 love+=random.randint(1,10)

import random
love +=random.randint(10,50)
if (love>100):
 love = 100

print("Calculating...")
import time
import random
time.sleep(random.randint(1,3))

print("",name1,"and",name2,"have a",love,"% relationship.")
if ((love>90) or (love == 90)):
 print("They have an unbreakable relationship that will last 
 forever.")
if ((love<89) or (love == 89)) and ((love>70) or (love == 70)):
 print("They have a strong relationship that will most likely 
 lead to a marriage.")
if ((love<69) or (love == 69)) and ((love>50) or (love == 50)):
 print("They have a good relationship that can lead to a 
 honeymoon to Paris.")
if ((love<49) or (love == 49)):
 print("They have a weak relationship that could have been a 
 'match made in heaven'.")

python calculator generator

share

asked 3 mins ago

MustafaMustafa

11

New contributor

Mustafa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

add a comment | 

$begingroup$

My love calculator gives a result from 0 to 100% based on these factors:

1. If the first letters of the names are the same.


2. If the number of vowels is the same.


3. If the length of the name is the same.


4. If the number of consonants is the same.

Also, there is an extra boost of 10-50%, so the result is also partially as a result of luck.
Can the coding below be simplified or improved to function more smoothly?:

name1 = input("Please type Name 1.n")
name2 = input("Please type Name 2.n")

total_vowel1 =0
for i in ['a','e','i','o','u']:
 total_vowel1 += name1.count(i)
total_vowel2 =0
for i in ['a','e','i','o','u']:
 total_vowel2 += name2.count(i)

love = 0
if(total_vowel1 == total_vowel2):
 import random
 love +=random.randint(10,30)

consonants1 = 0
consonants2 = 0
CONSONANTS = 'bcdfghjklmnprstvwxyz'
consonants1 = len([letter for letter in name1 if letter.lower() in 
CONSONANTS])
consonants2 = len([letter for letter in name2 if letter.lower() in 
CONSONANTS])

if(consonants1 == consonants2):
 import random
 love +=random.randint(20,40)

line1 = name1
line2 = name2
split1 = line1.split()
split2 = line2.split()
fl1 = [word[0] for word in split1]
fl2 = [word[0] for word in split2]

if (fl1 == fl2):
 import random
 love +=random.randint(10,30)

if (len(name1) == len(name2)):
 import random
 love+=random.randint(1,10)

import random
love +=random.randint(10,50)
if (love>100):
 love = 100

print("Calculating...")
import time
import random
time.sleep(random.randint(1,3))

print("",name1,"and",name2,"have a",love,"% relationship.")
if ((love>90) or (love == 90)):
 print("They have an unbreakable relationship that will last 
 forever.")
if ((love<89) or (love == 89)) and ((love>70) or (love == 70)):
 print("They have a strong relationship that will most likely 
 lead to a marriage.")
if ((love<69) or (love == 69)) and ((love>50) or (love == 50)):
 print("They have a good relationship that can lead to a 
 honeymoon to Paris.")
if ((love<49) or (love == 49)):
 print("They have a weak relationship that could have been a 
 'match made in heaven'.")

python calculator generator

share

asked 3 mins ago

MustafaMustafa

11

New contributor

Mustafa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

name1 = input("Please type Name 1.n")
name2 = input("Please type Name 2.n")

total_vowel1 =0
for i in ['a','e','i','o','u']:
 total_vowel1 += name1.count(i)
total_vowel2 =0
for i in ['a','e','i','o','u']:
 total_vowel2 += name2.count(i)

love = 0
if(total_vowel1 == total_vowel2):
 import random
 love +=random.randint(10,30)

consonants1 = 0
consonants2 = 0
CONSONANTS = 'bcdfghjklmnprstvwxyz'
consonants1 = len([letter for letter in name1 if letter.lower() in 
CONSONANTS])
consonants2 = len([letter for letter in name2 if letter.lower() in 
CONSONANTS])

if(consonants1 == consonants2):
 import random
 love +=random.randint(20,40)

line1 = name1
line2 = name2
split1 = line1.split()
split2 = line2.split()
fl1 = [word[0] for word in split1]
fl2 = [word[0] for word in split2]

if (fl1 == fl2):
 import random
 love +=random.randint(10,30)

if (len(name1) == len(name2)):
 import random
 love+=random.randint(1,10)

import random
love +=random.randint(10,50)
if (love>100):
 love = 100

print("Calculating...")
import time
import random
time.sleep(random.randint(1,3))

print("",name1,"and",name2,"have a",love,"% relationship.")
if ((love>90) or (love == 90)):
 print("They have an unbreakable relationship that will last 
 forever.")
if ((love<89) or (love == 89)) and ((love>70) or (love == 70)):
 print("They have a strong relationship that will most likely 
 lead to a marriage.")
if ((love<69) or (love == 69)) and ((love>50) or (love == 50)):
 print("They have a good relationship that can lead to a 
 honeymoon to Paris.")
if ((love<49) or (love == 49)):
 print("They have a weak relationship that could have been a 
 'match made in heaven'.")

share

asked 3 mins ago

MustafaMustafa

11

New contributor

Mustafa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share

asked 3 mins ago

MustafaMustafa

11

New contributor

Mustafa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 3 mins ago

MustafaMustafa

11

New contributor

Mustafa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 3 mins ago

MustafaMustafa

11